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What are the answers to Holt chemistry's stoichiometry problem solving packet?
Na2CO3+2H(C2H3O2) >2Na(C2H3O2) + CO2+H20
Which ions are in NaC2H3O2?
Na+ and C2H3O2- are the two ions in the compound sodium acetate.
A student added 100 ml of 0.10 m naoh to 250 ml of a buffer that contained 0.15 m hc2h3o2 and 0.25 m c2h3o2- what is the concentration of hc2h3o2 after the addition of the strong base?
CHEM 123 Solution to Ques 16.65 from Wiley #12 16.65 A student added 100 mL of 0.10 M NaOH to 250 mL of a buffer that contained 0.15 M HC2H3O2 and 0.25 M C2H3O2−. What is the concentration of HC2H3O2 after the addition of the strong base. Begin by writing the equation for the buffer (acid dissociation of the weak acid) HC2H3O2 + H2O H3O + + C2H3O2- Ka = 1.8 × 10-5 Initial amounts in the solution are: # mol C2H3O2- = (0.25 mol/L)(0.25 L) = 0.063 mol C2H3O2- # mol HC2H3O2 = (0.15 mol/L)(0.25 L) = 0.038 mol HC2H3O2 The added base (0.100 L)(0.10 mol/L) = 0.010 mol NaOH) will react with the acetic acid present in the buffer solution: NaOH + HC2H3O2 ⎯→ H2O + NaC2H3O2 Assume the added base reacts completely (since it's a strong base with a weak acid). For each mole of base added, one mole of HC2H3O2 is converted to C2H3O2-. Since 0.010 mol of base is added, 0.010 mol of HC2H3O2 will be depleted from the initial amount (0.038 mol) and 0.010 mol C2H3O2− ADDITIONAL produced in this reaction (added to the initial amount of 0.063 mol C2H3O2−): # mol HC2H3O2final = (0.038 - 0.010) mol = 0.028 mol # mol C2H3O2-final = (0.063 + 0.010) mol = 0.073 mol The final volume of solution is 250 mL + 100 mL = 350 mL. AFTER the reaction with NaOH, the concentrations become… [HC2H3O2] = 0.028 mol/0.350L = 0.080 M HC2H3O2 [C2H3O2−] = 0.073 mol/0.350L = 0.21 M C2H3O2− In Wiley #12, the question asked only what the concentration of acetic acid becomes, so this would be the answer: 0.080 M. (The optional given you in Wiley was 0.079 M.) In the actual question in the book, it went further and asked you what is the CHANGE in concentration of HC2H3O2 and C2H3O2−, so you would simply go one further step: Initial conc of HC2H3O2 was 0.15M Change in conc = 0.15−0.080 = 0.0.07 M decrease in [HC2H3O2] Initial conc of C2H3O2− was 0.25M Change in conc = 0.25M − 0.21 Μ = 0.04 Μ decrease in [C2H3O2−]
What is AgC2H3O2 individual ions?
AgC2H3O2 dissociates into Ag+ and C2H3O2- ions. Ag+ is the silver ion with a +1 charge, and C2H3O2- is the acetate ion.
What is the name for the polyatomic ion C2H3O2?
This is the ion acetate.
What are the answers to Holt chemistry's stoichiometry problem solving packet?
Na2CO3+2H(C2H3O2) >2Na(C2H3O2) + CO2+H20
Which ions are in NaC2H3O2?
Na+ and C2H3O2- are the two ions in the compound sodium acetate.
A student added 100 ml of 0.10 m naoh to 250 ml of a buffer that contained 0.15 m hc2h3o2 and 0.25 m c2h3o2- what is the concentration of hc2h3o2 after the addition of the strong base?
CHEM 123 Solution to Ques 16.65 from Wiley #12 16.65 A student added 100 mL of 0.10 M NaOH to 250 mL of a buffer that contained 0.15 M HC2H3O2 and 0.25 M C2H3O2−. What is the concentration of HC2H3O2 after the addition of the strong base. Begin by writing the equation for the buffer (acid dissociation of the weak acid) HC2H3O2 + H2O H3O + + C2H3O2- Ka = 1.8 × 10-5 Initial amounts in the solution are: # mol C2H3O2- = (0.25 mol/L)(0.25 L) = 0.063 mol C2H3O2- # mol HC2H3O2 = (0.15 mol/L)(0.25 L) = 0.038 mol HC2H3O2 The added base (0.100 L)(0.10 mol/L) = 0.010 mol NaOH) will react with the acetic acid present in the buffer solution: NaOH + HC2H3O2 ⎯→ H2O + NaC2H3O2 Assume the added base reacts completely (since it's a strong base with a weak acid). For each mole of base added, one mole of HC2H3O2 is converted to C2H3O2-. Since 0.010 mol of base is added, 0.010 mol of HC2H3O2 will be depleted from the initial amount (0.038 mol) and 0.010 mol C2H3O2− ADDITIONAL produced in this reaction (added to the initial amount of 0.063 mol C2H3O2−): # mol HC2H3O2final = (0.038 - 0.010) mol = 0.028 mol # mol C2H3O2-final = (0.063 + 0.010) mol = 0.073 mol The final volume of solution is 250 mL + 100 mL = 350 mL. AFTER the reaction with NaOH, the concentrations become… [HC2H3O2] = 0.028 mol/0.350L = 0.080 M HC2H3O2 [C2H3O2−] = 0.073 mol/0.350L = 0.21 M C2H3O2− In Wiley #12, the question asked only what the concentration of acetic acid becomes, so this would be the answer: 0.080 M. (The optional given you in Wiley was 0.079 M.) In the actual question in the book, it went further and asked you what is the CHANGE in concentration of HC2H3O2 and C2H3O2−, so you would simply go one further step: Initial conc of HC2H3O2 was 0.15M Change in conc = 0.15−0.080 = 0.0.07 M decrease in [HC2H3O2] Initial conc of C2H3O2− was 0.25M Change in conc = 0.25M − 0.21 Μ = 0.04 Μ decrease in [C2H3O2−]
What happen went Pure barium is added to a solution of silver acetate?
When pure barium is added to a solution of silver acetate, a double displacement reaction occurs. Barium acetate and silver metal are formed as products. Additionally, barium sulfate may also form if sulfate ions are present in the solution.
What is AgC2H3O2 individual ions?
AgC2H3O2 dissociates into Ag+ and C2H3O2- ions. Ag+ is the silver ion with a +1 charge, and C2H3O2- is the acetate ion.
What is the name of C2H302- ion?
C2H3O2- is the acetate ion.
What is the name for the polyatomic ion C2H3O2?
This is the ion acetate.
What species are present in aqueous HC2H3O2?
In aqueous HC2H3O2 solution, species present are acetic acid (HC2H3O2) molecules and hydronium ions (H3O+). The acetic acid molecules can partially dissociate to form acetate ions (C2H3O2-) and hydronium ions.
What is vinegar made up of?
vinegar is made up of H2O and acetic acid 5%.
Is an aqueous solution Lic2h3o3 acidic basic or neutral?
An aqueous solution of LiC2H3O2 is slightly basic. This is because the acetate ion (C2H3O2−) is the conjugate base of acetic acid, which is a weak acid. The presence of this ion makes the solution slightly basic.
What is the formula of boron acetate?
The formula for boron acetate is B(C2H3O2)3.
What is the formula for erbium acetate?
The formula for erbium acetate is Er(C2H3O2)3.
