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Is hno3 plus H2O -----h3o plus no3 an acid or base?
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
How do you prepare 0.01 M from 65 percent HNO3?
The molar mass of HNO3 is 63 gram/mol and of water is 18 gram/mol. Lets assume that the density of the HNO3 + water mixture is equal to the density of water at room temperature is 1000 gram/L. 0.01 M is equal to 0.01 mol HNO3 per liter HNO3 + water. Multiplying the molar mass of HNO3 by the molarity shows this is equal to 0.63 gram HNO3 per liter HNO3 + water. Using the density of water shows that this is equal to 0.000063 gram HNO3 per gram water. This is therefore 0.0065 percent by weight. (The assumption that the density of the mixture is approximately equal to that of pure water seems justified because the amount of HNO3 in the mixture is very low) Assuming we start with an initial 65 percent by weight of HNO3 (10.3 M using the same type of calculation), water will need to be added to dilute to 0.0065 percent (0.01M). To find the required amount of water that is added a total and component mass balance can be used. The total mass balance is given by: Mt = M0 + Ma Here, M0 is the initial amount of water + HNO3, Ma is the added amount of (pure) water and Mt is the total mass of the water + HNO3 after adding more water. The component mass balance over HNO3 is given by: xtMt = x0M0 + xaMa= x0M0 Where xt is the final weight fraction of HNO3 in water, x0 is the initial weight fraction in water and xa is the weight fraction of HNO3 in pure water (which is logically equal to zero). Lets say we have a starting mass M0 = 100 gram HNO3 + water with the initial weight fraction x0 = 0.65 gram HNO3 per gram and we want a final weight fraction xt = 0.000065, rearranging for the total weight after having added water to reach this dilution gives: Mt = x0M0/xt = 0.65x100/0.000065 = 1000000 gram HNO3 + water The amount of water which needs to be added then simply follows from: Ma = Mt - M0 = 1000000 - 100 = 999900 gram water
What is the balanced equation for the reaction of nitric acid and sodium hydroxide?
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
Balance chemical equation for the dissociation of nitric acid in water?
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
Is HNO3 an acid or base when dissolved in water?
HNO3 is an acid.Its property remains same in water.
Is hno3 plus H2O -----h3o plus no3 an acid or base?
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
How do you prepare 0.01 M from 65 percent HNO3?
The molar mass of HNO3 is 63 gram/mol and of water is 18 gram/mol. Lets assume that the density of the HNO3 + water mixture is equal to the density of water at room temperature is 1000 gram/L. 0.01 M is equal to 0.01 mol HNO3 per liter HNO3 + water. Multiplying the molar mass of HNO3 by the molarity shows this is equal to 0.63 gram HNO3 per liter HNO3 + water. Using the density of water shows that this is equal to 0.000063 gram HNO3 per gram water. This is therefore 0.0065 percent by weight. (The assumption that the density of the mixture is approximately equal to that of pure water seems justified because the amount of HNO3 in the mixture is very low) Assuming we start with an initial 65 percent by weight of HNO3 (10.3 M using the same type of calculation), water will need to be added to dilute to 0.0065 percent (0.01M). To find the required amount of water that is added a total and component mass balance can be used. The total mass balance is given by: Mt = M0 + Ma Here, M0 is the initial amount of water + HNO3, Ma is the added amount of (pure) water and Mt is the total mass of the water + HNO3 after adding more water. The component mass balance over HNO3 is given by: xtMt = x0M0 + xaMa= x0M0 Where xt is the final weight fraction of HNO3 in water, x0 is the initial weight fraction in water and xa is the weight fraction of HNO3 in pure water (which is logically equal to zero). Lets say we have a starting mass M0 = 100 gram HNO3 + water with the initial weight fraction x0 = 0.65 gram HNO3 per gram and we want a final weight fraction xt = 0.000065, rearranging for the total weight after having added water to reach this dilution gives: Mt = x0M0/xt = 0.65x100/0.000065 = 1000000 gram HNO3 + water The amount of water which needs to be added then simply follows from: Ma = Mt - M0 = 1000000 - 100 = 999900 gram water
What is the balanced equation for the reaction of nitric acid and sodium hydroxide?
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
What results from the combination of Nitrogen and Water?
HNO3
Balance chemical equation for the dissociation of nitric acid in water?
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
Is HNO3 an acid or base when dissolved in water?
HNO3 is an acid.Its property remains same in water.
Is HNO3 an electrolyte?
Yes. HNO3 is an electrolyte. In water, it will dissolve into H+ ions and NO3- ions.
What is the total equation for hno3 and koh?
It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
HNO3 is an example of a mixture or a solution?
HNO3 is not an example of a mixture. It is a solution of nitric acid in water where the nitric acid molecules are completely dissolved in water molecules.
Is HNO3 polar?
If its soluble in water it is polar so yes!
What are the formulas of the two products formed when nitric acid dissolves in water?
It is a dissociation reaction: HNO3---------H+ + (NO3)-
If hno3 is added to water how does pH- change?
If nitric acid (HNO3) is added to water, it decreases the concentration of hydroxide ions in solution. This is because nitric acid semi-strongly dissociates in water, following this chemical reaction: HNO3(aq) + H2O(l)-->NO3-(aq) + H3O+(aq) The hydronium ions that are created in this reaction then react quickly with the hydroxide ions in the water, as shown in this chemical equation: H3O+(aq) +OH-(aq) --> 2H2O(l) This results in fewer hydroxide ions existing in solution.
