c. H2O (l) H2O (g 0.010 atm) This is the true answer that the Mastering Chemistry Homework site gave.
Mg-Cl and K-I
C(s)+O2(g) -> CO2(g)
Between 1 and 2 kg/L KNO3 at 600C would be a good guess. This is based on rough data found in en.wikipedia: 133 g/L (0 °C) 383 g/L (25 °C) 2470 g/L (100 °C)
You need the balanced chemical reaction equation :------------------------------------------------------------------------2 K + 2 H2O ----. 2 KOH + H2moles H2 = n H2 = ( 1.60 L ) ( 1 mol H2 / 22.4 L H2 ) = 0.07143 moles H2moles K = n K = ( 0.07143 mol H2 ) ( 2 mol K / 1 mol H2 ) = 0.14286 moles Kmass K = m K = ( 0.14286 mol K ) ( 39.10 g K / mol K )mass K = m K = 5.56 g of potassium
a, a, b, b, c, c, d, d, e, e, f, f, g, g, h, h, i, i, j, j, k, k, l, l
a b c d e f g h i j k l m n OOOOOOOOOOOOOOO a b c d e f g h i j k l m n OOOOOOOOOOOOOOO
Chalk. C-L-I-C-K C-L-O-C-K C-L-U-C-K C-H-U-C-K C-H-I-C-K Croak Crack Crook Creek
I have the DS version. When you beat the game you go to the shinobi place in konoha village and you go up to konohamaru and type in the code, G J H L B F D E. you will unlock 9 tailed Kyuubi Naruto. if you are interested here are some other codes for characters and battles: A L J K B E D G Kankuro H F I C L K B G Temari C G H A J B E L The Third Hokage D K F I A B J L Gaara I K A G D E F L Gai J G D L K A I B Iruka G B E I D A L F Itachi Uchiha E B J D A G F L Jiraiya A H F B L E J G Orochimaru F G E H I D A L "The Legendary Haze Ninja!" mission B C E G K F H L "The Legendary Sannin!" mission H L B A K G C D "An Extreme Battle!" mission Keep in mind these can only be used after you beat the game.
H L B A K G C D "An Extreme Battle!" mission F G E H I D A L "The Legendary Haze Ninja!" mission B C E G K F H L "The Legendary Sannin!" mission D K F I A B J L Unlocks Gaara I K A G D E F L Unlocks Gai J G D L K A I B Unlocks Iruka G B E I D A L F Unlocks Itachi Uchiha E B J D A G F L Unlocks Jiraiya A L J K B E D G Unlocks Kankuro G J H L B F D E Unlocks Kyuubi Naruto A H F B L E J G Unlocks Orochimaru H F I C L K B G Unlocks Temari C G H A J B E L Unlocks The Third Hokage
ballroom
E a r t h l e a k a g e c i r c u i t b r e a k e r ( e l c b )
Unlock Itachi Uchiha: Enter the code G, B, E, I, D, A, L, F. Unlock Jiraiya: Enter the code E, B, J, D, A, G, F, L. Unlock Kankuro: Enter the code A, L, J, K, B, E, D, G. Unlock Kyuubi Naruto: Enter the code G, J, H, L, B, F, D, E. Unlock Gaara: Enter the code D, K, F, I, A, B, J, L. Unlock Temari: Enter the code H, F, I, C, L, K, B, G. Unlock The 3rd Hokage: Enter the code C, G, H, A, J, B, E, L. Unlock Gai: Enter the code I, K, A, G, D, E, F, L. Unlock Iruka: Enter the code J, G, D, L, K, A, I, B. Unlock Orochimaru: Enter the code A, H, F, B, L, E, J, G.
#include<iostream.h> #include<conio.h> void main() { clrscr(); int i,k,a[10],c[10],n,l; cout<<"Enter the no. of elements\t"; cin>>n; cout<<"\nEnter the sorted elments for optimal merge pattern"; for(i=0;i<n;i++) { cout<<"\t"; cin>>a[i]; } i=0;k=0; c[k]=a[i]+a[i+1]; i=2; while(i<n) { k++; if((c[k-1]+a[i])<=(a[i]+a[i+1])) { c[k]=c[k-1]+a[i]; } else { c[k]=a[i]+a[i+1]; i=i+2; while(i<n) { k++; if((c[k-1]+a[i])<=(c[k-2]+a[i])) { c[k]=c[k-1]+a[i]; } else { c[k]=c[k-2]+a[i]; }i++; } }i++; } k++; c[k]=c[k-1]+c[k-2]; cout<<"\n\nThe optimal sum are as follows......\n\n"; for(k=0;k<n-1;k++) { cout<<c[k]<<"\t"; } l=0; for(k=0;k<n-1;k++) { l=l+c[k]; } cout<<"\n\n The external path length is ......"<<l; getch(); }
c. H2O (l) H2O (g 0.010 atm) This is the true answer that the Mastering Chemistry Homework site gave.
C D E F G H I J K L M it is
Black Dragon is spelled B-L-A-C-K D-R-A-G-O-N.