Na is sodium which has a charge of +1. This is your cation
HCO3 is Hydrogen Carbonate which has a charge or -1. This is your anion.
Thus your final answer would be Sodium Bicarbonate
The reaction between sodium bicarbonate (NaHCO3) and nitric acid (HNO3) produces carbon dioxide (CO2), water (H2O), sodium nitrate (NaNO3), and some nitrogen oxides as byproducts.
When NaHCO3 is combined with CaCl2 and H2O, a reaction will occur. However, the specific products depend on the conditions of the reaction - typically, NaHCO3 will react with CaCl2 to form NaCl, CaCO3, and H2O.
Na2CO3 (sodium carbonate) plus H2O (water) and CO2 (carbon dioxide) will undergo a chemical reaction to form sodium bicarbonate (NaHCO3). The balanced chemical equation for this reaction is: Na2CO3 + H2O + CO2 -> 2 NaHCO3.
The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is: 2 NaHCO3 -> Na2CO3 + CO2 + H2O From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
The reaction between sodium bicarbonate (NaHCO3) and nitric acid (HNO3) produces carbon dioxide (CO2), water (H2O), sodium nitrate (NaNO3), and some nitrogen oxides as byproducts.
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
When NaHCO3 is combined with CaCl2 and H2O, a reaction will occur. However, the specific products depend on the conditions of the reaction - typically, NaHCO3 will react with CaCl2 to form NaCl, CaCO3, and H2O.
Na2CO3 (sodium carbonate) plus H2O (water) and CO2 (carbon dioxide) will undergo a chemical reaction to form sodium bicarbonate (NaHCO3). The balanced chemical equation for this reaction is: Na2CO3 + H2O + CO2 -> 2 NaHCO3.
The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is: 2 NaHCO3 -> Na2CO3 + CO2 + H2O From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
NaHCO3 ----> H2O Mass 2.10g 0.045g RAM 84 g/moles 18 g/moles number of moles 0.025moles 0.025moles
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
The reaction equation for sodium hydrogencarbonate (NaHCO3) with hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2 This reaction produces sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2) as products.
When sodium bicarbonate (NaHCO3) is heated, it decomposes into sodium carbonate (Na2CO3), water (H2O), and carbon dioxide (CO2) gas. This reaction occurs as the bicarbonate ion decomposes to form the carbonate ion, releasing water and carbon dioxide in the process.
The balanced equation for the reaction between acetic acid (CH3COOH) and sodium hydrogen carbonate (NaHCO3) is: CH3COOH + NaHCO3 -> CH3COONa + H2O + CO2 This reaction produces sodium acetate (CH3COONa), water (H2O), and carbon dioxide (CO2).
The reactants are sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl). These react to form sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2) as products.
The equation for the reaction of benzoic acid and NaHCO3 is as follows: C6H5COOH + NaHCO3 ===> C6H5COO-Na+ + H2O + CO2