0
In compounds such as H2Se yes it is, and the oxidation number ofd -2 is well known. However there are many compounds where Se has other oxidation numbers (Se is very similar to Sulfur another group 16 elemnt) for example compounds where Se has an ox number of +4, SeF4, +6, SeF6, -1 in the polyselenide compound Na2Se2
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∙ 10y ago
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∙ 13y ago+6 is the highest. All of the oxidation numbers for Se are -2, +2,+4, and +6.
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∙ 11y agoNa2SeSO3
+1 for each Na, -2 for Se, +6 for S and -2 for each O
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∙ 11y ago+1 for each H, -2 for each O, +4 for Se
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∙ 10y agoZero. Se8 is an allotrope of selenium and in the elemental form all elements have an oxidation state of zero
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Determine the oxidation number os Se in K2SeO4?
The oxidation number of oxygen is 2- and the oxidation number of potassium is 1+. Seeing as the molecule is neutral we can easily work out that the oxidation number of Se as 6+. (-8 + 2 = +6)
What is the oxidation number of N?
The oxidation number of N, or Nitrogen, is N-3. Nitrogen is in group five, meaning it has five valence electrons. It needs to get eight to be stable. So it will gain 3 electrons to be stable. If you gain electrons, that makes it a negative number since electrons are negative in charge.
What does the oxygen atom in a water molecule have charge?
The oxygen in a water molecule doesn't really have a "charge" per se. It is partially negative relative to the hydrogen atoms which are partially positive. The oxidation number of oxygen in water is 2-, however, but this isn't really a "charge".
Why is tin IV selenide SnSe2?
Tin(IV) has a positive four charge. Selenide usually forms a 2- ion. Ionic compounds need a neutral, balanced charge. With the above information, the rest is pretty much just math. Tin - Sn(+4) Selenide - Se(-2) So you need two of Se to balance the +4 with a -4. = SnSe2 The answer above is OK, however if you are familiar with the idea of oxidation states SnIV is tin in its 4th oxidation state. Selenium has a common oxidation stae of -2 and once again you can do the math. The bonding in SnSe2 is not ionic so using oxidation states is preferable.
Which element Mo Se Na or Br contains the most moles of atoms in a 1.0 gram sample?
This element is sodium.
What is the oxidation state for selenium?
Oxidation number of Se is +6. Oxidation number of O is -2.
Determine the oxidation number os Se in K2SeO4?
The oxidation number of oxygen is 2- and the oxidation number of potassium is 1+. Seeing as the molecule is neutral we can easily work out that the oxidation number of Se as 6+. (-8 + 2 = +6)
What is the predicted oxidation number for Al and Se?
0 in their compounds, +3 for Al and -2 for Se in their compounds.
What is the oxidation number of N?
The oxidation number of N, or Nitrogen, is N-3. Nitrogen is in group five, meaning it has five valence electrons. It needs to get eight to be stable. So it will gain 3 electrons to be stable. If you gain electrons, that makes it a negative number since electrons are negative in charge.
What is the oxidation state for Se?
Selenium's most common oxidation state is -2, as it is both a non metal, and is located in the periodic table in the same group as O and S.
What is the scientific abbreviation of sodium and water?
It doesn't have an abbreviation per se. Its atomic symbols is Na.NA
Serial number Red-Lynx Trials 2 SE demo?
Serial number Red-Lynx Trials 2 SE?
What does the oxygen atom in a water molecule have charge?
The oxygen in a water molecule doesn't really have a "charge" per se. It is partially negative relative to the hydrogen atoms which are partially positive. The oxidation number of oxygen in water is 2-, however, but this isn't really a "charge".
What is the atomic number of se?
The atomic number of Selenium is 34.
Sayaron main suraj se zameen kon se number per hai?
3
Is selenium the same as selenate?
No. Both are different. Sodium selenide is an ionic compound by the formula Na2Se. Sodium selenite is Na2SeO3, a selenite is the analog of sulfite. Selenium is a nonmetal with the symbol, Se.
Why is tin IV selenide SnSe2?
Tin(IV) has a positive four charge. Selenide usually forms a 2- ion. Ionic compounds need a neutral, balanced charge. With the above information, the rest is pretty much just math. Tin - Sn(+4) Selenide - Se(-2) So you need two of Se to balance the +4 with a -4. = SnSe2 The answer above is OK, however if you are familiar with the idea of oxidation states SnIV is tin in its 4th oxidation state. Selenium has a common oxidation stae of -2 and once again you can do the math. The bonding in SnSe2 is not ionic so using oxidation states is preferable.
