Formula: Pt3P4
It can also be written as Pt3(P)4 to distinguish it from containing the P43- ion
The chemical symbol for titanium IV phosphide is Ti3P4.
The molecular formula for ruthenium IV phosphide is RuP. Ruthenium has an oxidation state of +4, represented by the roman numeral IV, and phosphorus has an oxidation state of -3. Therefore, one ruthenium atom combines with one phosphorus atom to form RuP.
Platinum(IV) nitride has the chemical formula Pt3N4.
The molecular formula for ruthenium IV phosphide is RuP, and for uranium VI nitride, it is UN2. The formula Se2Cl2 represents diselenium dichloride, and Ni2CO3 is nickel(II) carbonate.
The chemical formula for platinum IV chloride is PtCl4. It consists of one platinum atom bonded to four chloride atoms.
Platinum (with a chrage of +4) and Phosphorous (with a charge of -3), together in this equation they form Platinum(IV)Phosphide.
Tin (IV) phosphide
The chemical symbol for titanium IV phosphide is Ti3P4.
The molecular formula for ruthenium IV phosphide is RuP. Ruthenium has an oxidation state of +4, represented by the roman numeral IV, and phosphorus has an oxidation state of -3. Therefore, one ruthenium atom combines with one phosphorus atom to form RuP.
Platinum Box IV was created on 2003-12-17.
The formula for platinum(IV) oxide is PtO2. Platinum has a 4+ oxidation state in this compound, which is represented by the Roman numeral IV in its name.
The chemical name for PtI4 is platinum(IV) iodide.
Platinum(IV) nitride has the chemical formula Pt3N4.
The chemical formula for platinum IV nitride is PtN2.
The molecular formula for ruthenium IV phosphide is RuP, and for uranium VI nitride, it is UN2. The formula Se2Cl2 represents diselenium dichloride, and Ni2CO3 is nickel(II) carbonate.
The chemical formula for platinum IV chloride is PtCl4. It consists of one platinum atom bonded to four chloride atoms.
The chemical name of PtO2 is platinum oxide.