rubidium sulfide
No, Rb2S is not a covalent compound. It is an ionic compound formed by the combination of the metal rubidium (Rb) and the non-metal sulfur (S), where rubidium donates its electrons to sulfur to form an ionic bond.
The formula for this compound is Rb2S.
The formula for the ionic compound formed between rubidium and sulfur is Rb2S. Rubidium is a group 1 element with a +1 charge, and sulfur is a group 16 element with a -2 charge. To balance the charges, two rubidium atoms are needed for every sulfur atom.
Rubidium sulfide, with the chemical formula Rb2S, features ionic bonds.
The chemical formula for rubidium sulfide is Rb2S. Rubidium is a group 1 element with a +1 charge, while sulfide is a group 16 element with a -2 charge, so two rubidium ions are needed to balance the charge of one sulfide ion.
Rb2S, or rubidium sulfide, is not a metal; it is a compound composed of rubidium, which is an alkali metal, and sulfur, which is a non-metal. In this compound, rubidium exists in the form of cations (Rb⁺), while sulfur forms anions (S²⁻). The overall structure of Rb2S is ionic, characteristic of metal-nonmetal combinations. Therefore, while it contains a metal, Rb2S itself is not classified as a metal.
No, Rb2S is not a covalent compound. It is an ionic compound formed by the combination of the metal rubidium (Rb) and the non-metal sulfur (S), where rubidium donates its electrons to sulfur to form an ionic bond.
The formula for this compound is Rb2S.
Rb(2)S(2)O(3) That's 2 atoms of Rubidium, 2 atoms of Sulfur, and 3 of Oxygen.
The formula for the ionic compound formed between rubidium and sulfur is Rb2S. Rubidium is a group 1 element with a +1 charge, and sulfur is a group 16 element with a -2 charge. To balance the charges, two rubidium atoms are needed for every sulfur atom.
The chemical formula for the compound formed between rubidium and sulfur is Rb2S. Rubidium is in Group 1 of the periodic table with a +1 oxidation state, while sulfur is in Group 16 with a -2 oxidation state, so they combine in a 1:1 ratio to form Rb2S.
Rubidium sulfide, with the chemical formula Rb2S, features ionic bonds.
Basically, the formula is K2S.This answer is more complicated: It adopts "antifluorite structure," which means that the small K+ ions occupy the tetrahedral (F−) sites in fluorite, and the larger S2− centers occupy the eight-coordinate (Ca2+) sites. Li2S, Na2S, and Rb2S crystallize similarly.
The chemical formula for rubidium sulfide is Rb2S. Rubidium is a group 1 element with a +1 charge, while sulfide is a group 16 element with a -2 charge, so two rubidium ions are needed to balance the charge of one sulfide ion.
TRANSISTOR PHASE SHIFT OSCILLATORCIRCUIT DIAGRAM:THEORY:The Transistor Phase Shift Oscillator produces a sine wave of desired designed frequency. The RC combination will give a 60° phase shift totally three combination will give a 180° phase shift. . The BC107 is in the common emitter configuration. Therefore that will give a 180° phase shift totally a 360° phase shift output is produced. The capacitor value is designed in order to get the desired output frequency. Initially the C and R are connected as a feedback with respect to input and output and this will maintain constant sine wave output. CRO is connected at the output.DESIGN:Given : Vcc = 12V , fo = 1 KHz,C = 0.01µF; IE = 5mA.; Stability factor = 10f = 1/ 2πRC Find RR1 = (Ri - R)R >> RcΒeta = -1 / 29Amplifier Design :Gain formula is given byAv = -hfe RLeff / hie ( Av = 29, design given )Assume, VCE = Vcc / 2RLeff = R c | | RLre = 26mV / IEhie = β re where re is internal resistance of the transistor.hie = hfe reVE = Vcc / 10On applying KVL to output loop,Vcc = IcRc + VCE + IEREVE = IERERc = ?Since IB is very small when compared with IcIc approximately equal to IERE = VE / IE = ?VB = VBE + VEVB = VCC . RB2 / RB1 + RB2S = 1+ RB / RERB =?RB = RB1|| RB2Find RB1 & RB2Input Impedance, Zi = (RB || hie )Coupling and bypass capacitors can be thus found out.Input coupling capacitor is given by , Xci = Z i / 10Xci = 1/ 2pf CiCi = ?output coupling capacitor is given by ,Xc0 = 1/ 2pf CoCo =?By-pass capacitor is given by, XCE = 1/ 2pf CECE =?