There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
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∙ 2012-09-04 19:15:08Pritam Singh
C4h10 hybridization
Pritam Singh
C4h10
The central atom is oxygen with sp3 hybridization.
The hybridization in the central I atom is sp3.
The hybridization of the central atom in NOCl is sp2.
The VSEPR formula for the nitrogen atom as the central atom in glycine is Ax3e.
In this compound, the central atom, sulfur, has one lone pair and four bond pairs, and it takes the see-saw shape according to VSEPR theory. Its hybridisatio is approximately sp3d
Sp2,120 is the hybridization of the central atom in SO2.
The central atom is oxygen with sp3 hybridization.
The hybridization of the central atom in NOCl is sp2.
The hybridization in the central I atom is sp3.
The VSEPR formula for the nitrogen atom as the central atom in glycine is Ax3e.
In this compound, the central atom, sulfur, has one lone pair and four bond pairs, and it takes the see-saw shape according to VSEPR theory. Its hybridisatio is approximately sp3d
Its hybridization is sp3d
The hybridization of the carbon atom in this molecule is sp2.
The central atom undergoes sp3d2 hybridization.
SP hybridization
sp3 would be the hybridization
Prsumably you mean AlH4- the tetrahydroaluminate anion. The hybridization of the central atom of AlH4 is sp3.