Niobium (Nb)
That element would be carbon.
Okay there has to be one.... I'm not sure either, i am doing a science project, so email me if u figure it out please! Its in the Vanadium Family :) ok person who eve wrote this vanadium is in the alkali metals family... oh and have fun with your science project -kodybear:)
The electron configuration for boron is 1s2 2s2 2p1, where the first two electrons fill the 1s orbital, the next two fill the 2s orbital, and the last electron occupies the 2p orbital. Boron has 5 total electrons.
Explore key information about the chemical elements through this periodic table Group 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 Period 1 1H 2He 2 3Li 4Be 5B 6C 7N 8O 9F 10Ne 3 11Na 12Mg 13Al 14Si 15P 16S 17Cl 18Ar 4 19K 20Ca 21Sc 22Ti 23V 24Cr 25Mn 26Fe 27Co 28Ni 29Cu 30Zn 31Ga 32Ge 33As 34Se 35Br 36Kr 5 37Rb 38Sr 39Y 40Zr 41Nb 42Mo 43Tc 44Ru 45Rh 46Pd 47Ag 48Cd 49In 50Sn 51Sb 52Te 53I 54Xe 6 55Cs 56Ba * 71Lu 72Hf 73Ta 74W 75Re 76Os 77Ir 78Pt 79Au 80Hg 81Tl 82Pb 83Bi 84Po 85At 86Rn 7 87Fr 88Ra ** 103Lr 104Rf 105Db 106Sg 107Bh 108Hs 109Mt 110Ds 111Rg 112Cp 113Uut 114Uuq 115Uup 116Uuh 117Uus 118Uuo *Lanthanoids * 57La 58Ce 59Pr 60Nd 61Pm 62Sm 63Eu 64Gd 65Tb 66Dy 67Ho 68Er 69Tm 70Yb **Actinoids ** 89Ac 90Th 91Pa 92U 93Np 94Pu 95Am 96Cm 97Bk 98Cf 99Es 100Fm 101Md 102No
2The answer is 1 or two but:-Copper has an electronic configuration of [Ar] 3d10 4s1Copper is a transition metal and the simple concept of valence electrons is difficult to apply to these. You could say 1, expecting the 4s electron to be lost, which does happen to form Cu+ , cuprous, compounds. However copper readily forms Cu2+ in cupric compounds, e.g. in copper sulfate. In these one of the d electrons is also lost to give a d9 configuration.Other oxidation states such as copper (III) and copper(IV) are known.
Well it depends if you are an old schoool european or an old school american. Group 5B in Europe was the vanadium family so the answer would be Niobium, Nb in period 5. Group 5B in America was the nitrogen family so the answer would be antimony, Sb, in period 5. This confusion why there is an international convention that renumbered the groups, however it hasn't been universally adopted.
That element would be carbon.
The B in 5B EPR is the members performance rating. A scale of 1 to 5 is used and a 5 is the highest a member can earn.
-3-5b/7 = -4 Multiply all terms by 7: -21-5b = -28 Add 21 to both sides: -5b = -7 Divide both sides by -5 remembering that a -/- becomes a + Solution: y = 7/5 = 1.4
5b + 5b = 2 x 5b
-5b - 6 = -11, first add 6 to both sides --> -5b -6 + 6 = -11 + 6 --> -5b = -5Then divide both sides by (-5): b = 1. Last substitute your answer into the original equation to make sure it check out:-5*(1) - 6 = -11 --> -5 -6 = -11
Not sure how the problem is set up as I see a space between the minus sign and the 12 but not between the minus and the 2. But, using the numbers as written: To solve for b, you must form an equation (-5b -12 -2 = 0). Next you must separate the known numbers from the unknown by adding the sum of the knowns to both sides of the equation (-5b = 14). Then divide both sides of the equation by -5 to find the value of b (b = -2.8). No no no no no. It is -5b-14 because the -5b has no relation to the others so it stays as it is and then -12-2=-14 thus getting -5b-12-2=-5b-14. Cool.
-5b = 55 To get b by itself, divide both sides by -5. (-5b)/(-5) = (55)/(-5) -5 / -5 = 1, 55 / -5 = -11 1(b) = -11 b = -11
The GCF is 5b.
3
2a+5b isn't possible the answer is still 2a+5b.
To solve for b, you must form an equation (-5b -12 -2 = 0). Next you must separate the known numbers from the unknown by adding the sum of the knowns to both sides of the equation (-5b = 14). Then divide both sides of the equation by -5 to find the value of b (b = -2.8).