UV Light
Ethene has a very reactive double bond, and if mixed with bromine in organic solvent, it will undergo an addition reaction, where the two bromine atoms will adjoin onto the ethane molecule (because the double bond has broken, it now becomes an alkane (ethane) - more specifically it will form 1,2 - dibromoethane. C2H4 (g) + Br2 (tetrachloromethane) -------------------> CH2Br-CH2Br (aq) However, when bromine is dissolved in water instead, HOBr(aq) will be formed, subsequently the reaction becomes: C2H4 (g) + HOBr (aq) -------------------> HO-CH2-CH2Br (aq) Still, the brownish - reddish colour of the bromine water will decolourise. This is a useful way of distinguishing between alkanes and alkenes of similar molecular weights. ***RS**
when ethane reacts with Br in presence of sunlight, it forms Ethyl Bromide(C2H5Br) and then after dehydrohalogenation of the product obtained will give Ethlene (C2H4)
Yes it can undergo a substitution reaction, however conditions have to be just right. if there is a very limited amount of Bromine available OR it is at very high temperatures > 400 C. This will allow for a bromide radical to take the place of a Hydrogen atom on either side of the ethane molecule forming trans- 1,2-dibromoethane (primarily) with some of the cis form of the same molecule.Typically this is an addition reaction across the double bond of an ethene molecule resulting in the same products.
Alkanes like (methane, ethane, propane etc.) … They do not undergo addition reactions
CH3CH3 + Br2 + hv ==> CH3CH2Br (free radical halogenation)CH3CH2Br + NH3 ==> CH3CH2NH2 (Sn2)
1,2 dibromoethane and 1-bromo, 2-chloro ethane and 2-bromo ethanol
Ethene has a very reactive double bond, and if mixed with bromine in organic solvent, it will undergo an addition reaction, where the two bromine atoms will adjoin onto the ethane molecule (because the double bond has broken, it now becomes an alkane (ethane) - more specifically it will form 1,2 - dibromoethane. C2H4 (g) + Br2 (tetrachloromethane) -------------------> CH2Br-CH2Br (aq) However, when bromine is dissolved in water instead, HOBr(aq) will be formed, subsequently the reaction becomes: C2H4 (g) + HOBr (aq) -------------------> HO-CH2-CH2Br (aq) Still, the brownish - reddish colour of the bromine water will decolourise. This is a useful way of distinguishing between alkanes and alkenes of similar molecular weights. ***RS**
in first step prepare ethane to chloro ethane fallowed by wurtz reaction. chloro ethane can be prepared free radical reaction btw ethane and chlorine
when ethane reacts with Br in presence of sunlight, it forms Ethyl Bromide(C2H5Br) and then after dehydrohalogenation of the product obtained will give Ethlene (C2H4)
CH4 + Cl2 = CH3Cl + HCl (in presence of sun light) CH3Cl + Na/ether = CH3-CH3 + NaCl (ethane) this reaction is called wurtz reaction.........
Rust it is an oxide, formed by the reaction with oxygen or oxygenated water ; ethane don't react with water.
Yes, however it doesn't require it either to react. ethene+bromine water→1,2-dibromoethane Ethane reacts with bromine only in the presence of UV forming bromoethane and hydrogen bromide.
You are trying to reduce ethane to ethene, I am guessing. That is a very hard reaction to do... probably you will have to do a free radical halogenation on ethane to form 1-chloroethane, followed by an E2 reaction with t-butoxide or some other bulky base to form ethene. Since ethane and ethene are both gases and cheaply available from petroleum cracking, this reaction really isn't worth doing.
1 you will need an ester called vinyl acetate, to make the ester you need ethanoic acid and hydroxy ethane obtain ethane from crude oil by fractional distillation treat ethane with bromine in the presence of UV light. treat with aqueous NaOH to form ethanol we have got ethanol we need ethanoic acid add acidified potassium dichromate and conc H2SO4 condition: Heat under reflux.
Yes it can undergo a substitution reaction, however conditions have to be just right. if there is a very limited amount of Bromine available OR it is at very high temperatures > 400 C. This will allow for a bromide radical to take the place of a Hydrogen atom on either side of the ethane molecule forming trans- 1,2-dibromoethane (primarily) with some of the cis form of the same molecule.Typically this is an addition reaction across the double bond of an ethene molecule resulting in the same products.
The chemical reaction when C2H6 gas (ethane) is combusted is: 2C2H6 + 7O2 -> 4CO2 + 6H2O. Ethane reacts with oxygen to produce carbon dioxide and water.
You think probable to polymerization.