10.08g and 12.5 ml
The mass of the solution can be calculated by multiplying its volume (30.0 mL) by its density (1.60 g/mL). Mass = Volume x Density Mass = 30.0 mL x 1.60 g/mL = 48.0 grams.
The density of the salt solution is 1.14 g/ml. This is calculated by dividing the mass (57.0 g) by the volume (50.0 ml).
To calculate the density of the saline solution, you will need to know its mass. If the mass is not provided, you can't determine the density just based on the volume. Density is calculated as mass divided by volume.
d=m/v so 17.84/15.00 = 1.189 i hope its clear to you
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
A 30ml solution with a mass of 45g has a density of 45/30 or 1.5 g/ml, while a 40ml solution with a mass of 50g has a density of 50/40, or 1.25 g/ml. The 30ml solution with a mass of 45g has a higher density.
The density of the solution is 2.2 g/ml. Density is calculated by dividing the mass of the solution (22 g) by its volume (10 ml).
The mass of the solution can be calculated by multiplying its volume (30.0 mL) by its density (1.60 g/mL). Mass = Volume x Density Mass = 30.0 mL x 1.60 g/mL = 48.0 grams.
The density of the salt solution is 1.14 g/ml. This is calculated by dividing the mass (57.0 g) by the volume (50.0 ml).
density = mass / volume => 300g / 25.2ml ~= 11.9 g/ml
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
To calculate the density of the saline solution, you will need to know its mass. If the mass is not provided, you can't determine the density just based on the volume. Density is calculated as mass divided by volume.
The density of the salt solution is calculated by dividing the mass of the solution by its volume. In this case, the density would be 234 g divided by 210 mL, which equals 1.114 g/mL.
1.12g/ml
sp gr (0.850): Density of subbstance / density of water (1.00 g/mL) 0.850 = ? / 1.00 g/mL density of substance = 0.850 / 1.00 g/mL density of substance = 0.85 g/mL Density = mass (g) / volume (mL) 0.85 g/mL = 325 g / ? mL mL= 325 g / 0.85 g/ml mL = 382 Answer is: Volume of cleaning solution is 382 mL
The mass of the solution is the sum of the mass of NaCl and the mass of water. First, we calculate the mass of the solution by multiplying the density by the volume: 1.08 g/mL * 1100 mL = 1188 g. The mass percent of NaCl in the solution is then found by taking (mass of NaCl / mass of the solution) * 100%: (138 g / 1188 g) * 100% = 11.62%.
The mass of the solution is given by the volume multiplied by the density: 575 ml * 1.05 g/ml = 603.75 g. Since the solution is 18% NH4Cl, the mass of NH4Cl in the solution is 0.18 * 603.75 g = 108.675 g. Therefore, 575 ml of the solution contains 108.675 g of NH4Cl.