10.08g and 12.5 ml
5.84 M
The solution to this Q. is =DENSITY OF SOLUTION = MASS OF ACID / VOLUME OF ACID= 65.14 g / 35.4 ml= 1.84011 g/ml
100/80.6
30 mL water.
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
5.84 M
A 30ml solution with a mass of 45g has a density of 45/30 or 1.5 g/ml, while a 40ml solution with a mass of 50g has a density of 50/40, or 1.25 g/ml. The 30ml solution with a mass of 45g has a higher density.
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
density = mass / volume => 300g / 25.2ml ~= 11.9 g/ml
17 M
1.12g/ml
The solution to this Q. is =DENSITY OF SOLUTION = MASS OF ACID / VOLUME OF ACID= 65.14 g / 35.4 ml= 1.84011 g/ml
100/80.6
The mass is 38,75 g.
Volume of solution=V=240ml . Density of solution=d=1.13g/ml. Mass of solution=V*d=240*1.13=271.2g . Mass of solute=1.20g . PERCANTAGE W/W = 1.20/271.2*100=0.44%
0.3 grams/milliliter
sp gr (0.850): Density of subbstance / density of water (1.00 g/mL) 0.850 = ? / 1.00 g/mL density of substance = 0.850 / 1.00 g/mL density of substance = 0.85 g/mL Density = mass (g) / volume (mL) 0.85 g/mL = 325 g / ? mL mL= 325 g / 0.85 g/ml mL = 382 Answer is: Volume of cleaning solution is 382 mL