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Lewis dot structure:

Total Valence electrons in SO3: 24 Total Valence electrons required for a full octet in all atoms: 32 32-24=8 8/2= 4 bonds

Because it has 4 bonds and only need 3 to connect them all, it is a special type of bond (sorry i forgot what its called) but basically, the extra bond will be a part of another bond, creating a double bond. this extra bond will continually change to the other locations as shown here:

O=S-O O-S=O O-S-O | <--> | <--> O O O

Notice how the double bond rotates, since this happens really fast and randomly, the molecule is considered non-polar (triangular planer)

  • Be sure to include the correct number of unpaired electrons.

Another Opinion:

You need to pay attention to formal charges. If you use one double bond and two single bonds, your formal charges are thus:

Sulfur: 6 - 4 - 0 = 2

Double-bonded Oxygen: 6 - 2 - 4 = 0

Each single-bonded Oxygen: 6 - 3 - 4 = -1

The total formal charge adds to zero, which is good. However, it's better to disobey the octet rule for sulfur and double bond each oxygen to the sulfur atom. Then your formal charges are as follows:

Sulfur: 6 - 6 - 0 = 0

Each Oxygen: 6 - 2 - 4 = 0

All formal charges are zero. So, sulfur trioxide actually has three double bonds, and no unpaired electrons. This is accomplished by sulfur "unzipping" its valence shell and promoting two of its six valence electrons into the 3d sublevel, which gives sulfur 6 unpaired valence electrons. Then, each oxygen atom donates two electrons, but they each pair up with a different electron in sulfur's valence shell.

A similar thing happens with sulfur hexafluoride (SF6) -- except in that case, it's 6 single bonds to the central sulfur atom.

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