IO-
LiIO = Lithium hypoiodite LiIO2 = Lithium iodite LiIO3 = Lithium iodate LiIO4 = Lithium periodate
The chemical formula for potassium hypoiodite is KIO.
The chemical formula for lead(IV) hypoiodite is Pb(IO2)4.
IO- is an ion, not a compound. it is called the hypoiodite ion.
The formula for hypoiodite is IO-
LiIO = Lithium hypoiodite LiIO2 = Lithium iodite LiIO3 = Lithium iodate LiIO4 = Lithium periodate
The chemical formula for potassium hypoiodite is KIO.
The chemical formula for stannic hypoiodite is Sn(IO)4.
Hypoiodite ion
Calcium hypoiodite
To find the pOH from the given pH value (pH = 11.32), subtract the pH from 14 (pH + pOH = 14) to get pOH. Then use the pOH to find the hydroxide ion concentration in the solution. Finally, use the hydroxide ion concentration along with the initial concentration of hypoiodite ion to determine the KB value for the hypoiodite ion using the expression for the KB of a weak base.
The chemical formula for lead(IV) hypoiodite is Pb(IO2)4.
It is ammonium hypoiodite. Ammonium is NH4 Hypoiodite is IO- Hope this helps -Shangara Flora
IO- is an ion, not a compound. it is called the hypoiodite ion.
The formula for hypoiodite is IO-
Sodium hypoiodite
NaIO = Sodium Hypoiodite Sodium (Na+1) + Iodite (IO2-1) Hypoiodite= (IO-1) Na+1 + IO-1 = Na1IO1 but since we dont put a 1 subscript it is NaIO Since iodite lost 2 oxygens and it is a metal and a oxy-radical compound you have to add a hypo- prefix and a -ite suffix, which makes it Sodium Hypoiodite