the element phosphorus
Antimony (Sb, # 51) has 5 valence electrons (and so do all the other elements in that group.)
3
Boron has 3 valence electrons.Boron has 3 valence electrons.
Boron family is group IIIA so 3 electrons are in the outermost shell.
There are 26 valence electrons in NF3N: 1 (5) = 5 5+21=26F: 3 (7) = 21
Antimony (Sb, # 51) has 5 valence electrons (and so do all the other elements in that group.)
The valence electrons are the outermost (highest energy) s and p sublevels. There are 5 valence electrons in a phosphorus atom, and it is in period 3, so its valence electron configuration is 3s23p3.
They will gain 3 electrons from something with 3 valence electrons.
3
Boron has 3 valence electrons.Boron has 3 valence electrons.
Boron family is group IIIA so 3 electrons are in the outermost shell.
Atomic no. of nitrogen is 7 The valence electrons outside are 5 VALENCY= 8-5=3
There are 26 valence electrons in NF3N: 1 (5) = 5 5+21=26F: 3 (7) = 21
silver :)
3 valence electrons. As the atomic number of boron is 5, it would have 2 electrons in the first shell and 3 valence electrons in the second shell.
No such thing as pi3, but if you mean PI3, then there are 5 valence electron in P, and each I has 7 valence electrons for a total of 5 + 7 + 7 + 7 = 26 valence electrons.
5 valence electrons exist in bromine period, at ground state bromine has 3 valence electrons