and standard pressure po= 1 ATM (= 1.01325*105 Pa)
(At room temperature T=298 K and p=po the molar volume is 24.5 L/mole)
The molar volume of dry carbon dioxide (CO2) at standard temperature and pressure (STP) is approximately 22.4 liters per mole.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
The molar volume of dry carbon dioxide (CO2) at standard temperature and pressure (STP) is approximately 22.4 liters per mole.
The molar volume of hydrogen gas at STP (Standard Temperature and Pressure) is 22.4 liters per mole.
If you know moles of each use their molar masses to convert to mass.
At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
The volume of CO2 is 4,94 L.
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
Because at STP, Chloroform is liquid and Helium is in gaseous state. When something is in a gaseous state, it occupies a larger space than the liquid. I thought however, that chloroform would occupy less than that
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
Using the ideal gas law - the volume of a gas is independent of it composition and is determined solely by the equation PV=nRT. As one mole of CO would produce one mole of CO2 it would take 541 mL of CO to produce 541 mL of CO2.
At Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere pressure, the molar volume of an ideal gas is approximately 22.4 liters/mol. The molar mass of nitrogen gas (N₂) is approximately 28.02 grams/mol. To calculate the density (D) of nitrogen gas at STP, you can use the ideal gas law: � = Molar mass Molar volume at STP D= Molar volume at STP Molar mass � = 28.02 g/mol 22.4 L/mol D= 22.4L/mol 28.02g/mol � ≈ 1.25 g/L D≈1.25g/L Therefore, the density of nitrogen gas at STP is approximately 1.25 grams per liter.
Molar gas volume is the volume of ONE moel of gas. It only depends on the pressure and temperature, not on the kind of gas. Molar volume at standard temperature and standard pressure is always 22,4 Litres (for any gas)