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In cases of particular elements during reactions we see the change is their individual oxidation states.But if we have to calculate the equivalent weight of a species in a particular reaction,we have to find out the n factor for that particular species in the reaction.It is basically the overall exchange of electrons of a species per mole of that species in the reaction.
And 1 thing more,n factor can never be calculated for individual atoms.
For example:if we have to find out the equivalent weight of Fe2S3 in the reaction
Fe2S3 --> FeSO4 + SO2
First v balance the equation which gives
Fe2S3 + 502-->2FeSO4 +SO2
Then v find out the oxiadation states of S in d differsnt compounds cos v c that S is the only common element in all.In Fe2S3 The ox.state of s is -2.In FeS04 it's +6 n in SO2 it's +4.
So we c the net exchange of electrons per mole of Fe2S3 in d reaction is
2*(+6-(-2))+(4-(-2)) = (2*8)+6 =22
Therefore the n factor of Fe2S3 is 22.
So its equivalent weight will be Molecular weight/22.
What else can I help you with?
How do you account for the dilution factor when calculating the concentration of a solution?
To account for the dilution factor when calculating the concentration of a solution, you can use the formula: C1V1 C2V2. This formula helps you determine the final concentration (C2) after diluting a solution by a certain factor.
What are the units used to identify the concentration of a solution in terms of molarity, m?
The units used to identify the concentration of a solution in terms of molarity, M, are moles of solute per liter of solution.
How to prepare 0.2N HCl solution?
0.2 N HCl solution means 0.2 equivalents of HCl dissolved in 1 litre of water. Normality = Molarity x n-factor => Molarity =Normality/n-factor=0.2/1=0.2 M 0.2 moles should be present in 1 litre of solution. 0.2moles =0.2 x 36.5 = 7.3 grams of HCl =>Dissolve 7.3 grams of HCl in 1 litre if water to get a 0.2N solution.
How will you prepare one liter of 0.1 N HCL solution from 12 N HCL?
To prepare 1 liter of 0.1N HCl solution from 12N HCl, you would need to dilute the 12N HCl by a factor of 120. To do this, you would add approximately 83.33 mL of 12N HCl to a container and then dilute it with water to reach a final volume of 1 liter. Make sure to mix the solution thoroughly after dilution.
What is the unit of normality?
The unit for normality is N, or mol/LN or mol/Lit is the unit
What is the factor of n squared plus 2n?
Obviously, both terms have the common factor "n". You get the other factor by dividing both terms by n. The result is "n + 2".
How do you convert 0.1 N HCl to 0.01 N HCl?
To convert 0.1 N HCl to 0.01 N HCl, you can perform a dilution. For example, mix 10 mL of the 0.1 N HCl solution with 90 mL of distilled water to achieve a total volume of 100 mL, resulting in a 0.01 N HCl solution. The dilution factor here is 10, as you are reducing the concentration by a factor of ten.
How many sides will a 40 diagonals have?
If the polygon has n sides, it has n*(n - 3)/2 diagonals So, n(n - 3)/2 = 40 or n(n - 3)= 80 for which there is no solution. The question has no answer in terms of plane geometry.
Can you simplify 17 over 280?
No, because 17 is not a factor of 280. 17/280 is already i n lowest terms.
What is the solution to the equation n 12 17?
Without an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be an equation and so therefore there is no solution.
What is the complexity of the algorithm in terms of time and space when the keyword "algorithm" is used in a search?
The complexity of the algorithm in terms of time and space when the keyword "algorithm" is used in A search is typically O(bd), where b is the branching factor and d is the depth of the solution. This means that the time and space required by the algorithm grows exponentially with the depth of the solution and the branching factor of the search tree.
How do you solve by factoring if you only have something like n squared plus 5n equals 0?
n^2 + 5n = 0Where there is no constant term, then there is one monomial and one binomial factors. In this case the monomial is n and the binomial is (n + 5) So n*(n + 5) = 0 which leads to the solutions n = 0 or n = 5.
How to calculate n factor of acids?
N-factor of an acid is its basicity or the no. of H+ ions it produces on dissociation per molecule of acid. Generally, it equal to the no. of H+ ions present in the molecule but in some cases it is different. For example n-factor of some acids are:- HCl :-1 H2SO4:-2 H3PO4:- 3 H3PO3:- 2 H3PO2:-1 CH3COOH:-1
What is the nth term of ap if sum of n terms of ap is 2n plus 1?
There is no solution to the question as asked. If the sum of n terms is 2n+1 then the sum of n+1 terms, using the same formula, is 2*(n+1)+1 = 2n+2+1 = 2n+3 So the (n+1)th term is sum to n+1 minus sum to n = (2n+3) - (2n+1) = 2 So each term is 2. But if each term is 2, then the sum of n terms must be even. The sum is clearly odd - which leads to a contradiction.
What is the solution set of 18 - 3n plus 2 equals n plus 20 - 4n?
18 - 3n + 2 = n + 20 - 4n gather terms together on both sides of equation - 3n + 20 = - 3n + 20 0 = 0 =============no true solution here Actually, it's an infinite number, not "no solution" because it can also be done to end with n=n. I realize you didn't strictly say "no solution" but that's what it sounds like, so I'm just clarifying. -3n+20=-3n+20 -3n=-3n n=n
How do you calculate normality of a solution?
Normality (N) is calculated by dividing the molarity (M) of a solution by the equivalent factor (EF) of the solute. The equivalent factor is determined by the number of ions produced or reacted per molecule of solute. The formula for calculating normality is N = M x EF.
Which expression is equal to 12m 12n?
The expression 12m + 12n is equal to 12 times the sum of m and n. This expression cannot be simplified further unless there are like terms that can be combined. If m and n are like terms, then the expression can be further simplified by factoring out the common factor of 12 to get 12(m + n).
