the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
For a monatomic ion, the oxidation number is the same as the ion charge. So for K2SO4(which consists of 2 K+ ions and 1 SO42- ions) , the oxidation number of K is +1
+4
Oxygen= (-2)3=-6
Potassium= (+1)2=+2
Sulfur=?
(-6)+(+2)=+4
H = +1
O = -2
So...
2*1 + 4*-2 = -6
So to get an overall oxidation number of 0 therefore S has to be +6
Sulphur's oxidation number is +6. Its maximum oxidation number.
+1 for each K and -2 for S
+6
+6
7/2
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
2 k + h2so4 = k2so4 + h2
+1 for K -2 for each O +5 for N
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
+1 for each K, +6 for S and -2 for each O in K2SO4
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
2 k + h2so4 = k2so4 + h2
+1 for K -2 for each O +5 for N
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
It's K + H2SO4= K2SO4 +H2
+1 for K and -1 for Cl
+1 for K -1 for F
Ionic, K2SO4 has K+ cations and SO42- anions. The sulfate anions contain covalent bonds.
The Stock system is not used for these salts because the cations have only 1 oxidation number. So, for Rb and K it is 1+ and for Ca it is 2+ and for Al it is 3+. The stock system is used for the transition metals to indicate which oxidation state they are in.
+1 for each K, -3 for N