The reaction as written isn't balanced. It should be 2Al + 3Br2 ==> 2AlBr3
In this case Al is oxidized and Br2 is reduced
Aluminium Bromide = AlBr3
it is dimeric form of Aluminium bromide AlBr3
The chemical reaction isȘAlI3 + 3 Br2 = 2 AlBr3 + 3 I2
What is the chemical formula for Aluminum bromide?AlBr3(s) Al3+(aq) + 3Br-(aq)
AlBr3
Aluminium Bromide = AlBr3
it is dimeric form of Aluminium bromide AlBr3
The chemical reaction isȘAlI3 + 3 Br2 = 2 AlBr3 + 3 I2
The reaction is:3 CCl4 + 4 AlBr3 = 3 CBr4 + 4 AlCl3
the charge of the bromide ion in AlBr3 is -1
Aluminium tribromide= AlBr3
What is the chemical formula for Aluminum bromide?AlBr3(s) Al3+(aq) + 3Br-(aq)
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
This chemical reaction is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
AlBr3
sp3
AlBr3