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To answer this question we will have to know which of the many oxides of iron you are targeting.

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(3 x 55.85)/(3 x 55.85 + 4 x 16)x100

=167.55/231.55 x 100

=72.4%

The percent by mass of oxygen in Fe2O3 is 30 %.

72%

72%

30

Q: What is percent by mass of oxygen in Fe2O3?

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in one molecule of Fe2O3 there would be 3 oxygen atoms

The molar mass of anhydrous iron(II) nitrate is 179,91 g.

To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.

Fe2O3 contains the elements Iron and Oxygen. It would have 2 Iron and 3 oxygen.

0.225

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There are two atoms of iron and three atoms of oxygen in the compound Fe2O3. The mass percent of iron is 69.943%

in one molecule of Fe2O3 there would be 3 oxygen atoms

The molar mass of anhydrous iron(II) nitrate is 179,91 g.

The percent by mass of oxygen in N2O4 is 69,56 %.

Mass of Fe=(Mass of Fe2O3)(Mr Fe/ Mr Fe2O3)

To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.

The mass percent of oxygen in SO2 is 50 %.

Fe2O3 contains the elements Iron and Oxygen. It would have 2 Iron and 3 oxygen.

0.225

The oxide Fe2O3 has 3 oxygen atoms in the molecule.

Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================

the answer is 29 percent