What is percent composition of AgNO2?

Answer 1

That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.

Answer 2

The percent composition of the elements in AgNO2 are: 70% Ag, 9% N, and 21% O.

To determine the percent composition of each element, divide the molar mass of each element by the molar mass of the compound and multiply by 100.

The molar mass of AgNO2 is 154 g/mol. The molar mass of Ag is 108 g/mol, the molar mass of N is 14 g/mol, and the molar mass of 2 O atoms is 32 g/mol.

Percent composition of Ag:

(108 g/mol Ag)/(154 g/mol AgNO2) x 100 = 70% Ag

Percent composition of N:

(14 g/mol N)/(154 g/mol AgNO2) x 100 = 9% N

Percent composition of O:

(32 g/mol O)/(154 g/mol AgNO2) x 100 = 21% O

Answer 3

The percent composition of AgNO2 is 58.92% Ag, 18.57% N, and 22.51% O. This means that in every 100 grams of AgNO2, there are approximately 58.92 grams of silver, 18.57 grams of nitrogen, and 22.51 grams of oxygen.

Answer 4

Silver nitrate contain 63,297 56 % silver.

Answer 5

The molar mass of silver nitrate is 169,87 - AgNO3.