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It's a 2 part sealing paint which is used on the inside of (fuel?) storage tanks.

There were many variations introduced by PR&C / Courtaulds / PRC-DeSoto.

From web searching, it appears that the original vesion and some variations have been superceeded.

It now appears to be known as "PS 890", followed by the variation.

Manufacturer History (approximate years) :

(source : Material Safety Data Sheets).

1981 - 1985 : Essex Chemical Corp (merged with Dow Chemical 1988)

1986 - 2000 : Products, Research & Chemicals Corp (DBA Courtaulds Aerospace)

2000 - present : PRC-DeSoto (part of PPG Industries from about 2000)

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12y ago

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What is the experimental molar heat of combustion of methane?

The standard enthalpy of combustion for methane is -890 kJ/mol.


What mass of natural gas CH4 must you burn to emit 270kJ of heat?

To calculate the mass of natural gas burned, we need to use the heat of combustion of methane, which is -890 kJ/mol. This means that 1 mol of CH4 produces 890 kJ of heat. Therefore, to emit 270 kJ of heat, you would need to burn 270/890 = 0.303 mol of CH4. The molar mass of CH4 is 16.05 g/mol, so the mass of CH4 needed would be 0.303 mol * 16.05 g/mol = 4.86 g.


What can be said about a reaction with H -890 kJmol and S -0.24 kJ(mol K)?

The reaction is exothermic because the enthalpy change is negative (-890 kJ/mol). The reaction may be spontaneous at low temperatures due to the negative entropy change (-0.24 kJ/(mol K)), which decreases the overall spontaneity of the reaction.


What are the reactants when methane burns in oxygen?

The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D


What can be said about a reaction with h=-890 kj/mol and s = -0.24 kj/mol?

It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.