S, P, D, and F are the letters assigned to the four different orbital shapes. An orbital is the area around the nucleus of an atom where you find electrons. Not all atoms have the four shapes though; the most basic elements (Hydrogen, with one electron for example) start with the S shape only, and add more shapes, as they become more complex, adding in order of S, P, D, and finally F. Each orbital has a limit to how many electrons it can hold: S can only hold 2 electrons, P holds 6, D holds 10, and F holds 14. The S orbital is spherical, P looks something like a peanut, and D like a doughnut. The F orbital is very complex, rarely used, and only found in elements with very high atomic numbers.
Poorly worded question which makes little sense. Most elements have electrons in those sublevels, but elements are not contained within the sublevels, only electrons. For example, H has a single electron in a S sublevel, while Uranium has electrons in all of those sublevels, in many shells. The question is sort of like "How many ducks are there in a feather". Makes no sense.
these are sub shells of an atom, where 's' stands for 'sharp' and has 2 electrons, 'p' stands for 'principal' and has 6 electrons, 'd' stands for 'diffuse' and has 10 electrons, 'f' stands for 'fundamental' and has 14 electrons.
The s stands for spherical; the p stands for principle; the d stands for diffused; and the f stands for fundamental.
s is from sharp, p from principal, d from diffuse, f from fine; these were old names for spectral lines classification.
s = sharp
p = principle
d = diffuse
f = fundamental
subshells
faltu
Because their electronic configuration is ended at 'f' orbitals and can not be placed in 's','p' and 'd' blocks.
(n-1)d1-10ns1-2
The answer is: S,P,D,F. Beyond F they follow normal alphabetic order: G, H, I, etc.
Principal quantum numbers (n).
5s25p2 The 2's are exponents on the s and the p
the correct electronic confrigration of phosperous is 2,8,5
Actually it is about the orbitals of valence shells of sulphur. Sulphur has atomic no. 16 and electronic configuration 1s2,2s2,2p6,3s2,3p4. Its outer most shell has s.p.d and f orbitals from which s and p have electrons and d and f are vacant. When 2 electrons from p are transferred to d, the valency becomes +2. When two more electrons from p are transfered to d, the valency becomes +4. When two left electrons from s are transferred to d, the valency becomes +6.
Because their electronic configuration is ended at 'f' orbitals and can not be placed in 's','p' and 'd' blocks.
the correct electronic confrigration of phosperous is 2,8,5
F. P. D. has written: 'Mr. Dooley'
P D F. Murray has written: 'Biology'
s = ? , p=? , d=?, f=?
(n-1)d1-10ns1-2
The answer is: S,P,D,F. Beyond F they follow normal alphabetic order: G, H, I, etc.
Energy Level: Sublevels1: s2: s, p3: s, p, d4: s, p, d, f5: s, p, d, f, g6: s, p, d, f, g, h7: s, p, d, f, g, h, i
Electronic configuration is the arrangement of electrons in the respective shells of an atom when it is in its ground state,(where all of its electrons are in their respective lowest energy orbitals). This is shown as the number of electrons in the subshells s, p d, f, g. The subshells are in energy sequence, low to high. An example :- Osmium full electronic configuration 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s2 4d10 5p6 4f14 5d6 6s2 The filling of energy levels generally follows the aufbau principle.
P. D. Reynolds has written: 'A computer ABC' -- subject(s): Dictionaries, Electronic data processing, Electronic calculating machines