The ionic formula formed between barium and fluorine is BaF2. This compound consists of barium cations (Ba2+) and fluoride anions (F-) in a 1:2 ratio, following the octet rule for stability. Barium and fluorine have a strong electrostatic attraction due to the transfer of electrons from barium to fluorine, resulting in the formation of a stable ionic bond.
The formula for the compound formed between barium and nitrogen is Ba3N2, which is called barium nitride. Barium has a 2+ charge and nitrogen has a 3- charge, so the formula is derived from their charges balancing out to form a neutral compound.
The compound formed between nitrogen and barium is barium nitride (Ba3N2). The formula indicates that three barium atoms combine with two nitrogen atoms to form the compound.
Some basic information that I'm able to get from the formula BaF2 are: 1) The compound is composed of two different elements, Barium and Fluorine in the ratio of 1:2 2) Barium is a metal and Fluorine is a non-metal therefore BaF2 is formed by ionic bondings and it's an ionic compound 3) Barium donates one electron EACH to two Fluorine and the ions are Ba2+ and 2F- 4) BaF2 is a salt (metal + non-metal) 5) BaF2 has a giant lattice structure
The chemical formula for the compound formed between barium and bromine is BaBr2. In this compound, barium forms a +2 cation (Ba^2+) and bromine forms a -1 anion (Br^-), resulting in the formula BaBr2.
The ionic compound formed between barium and sulfur is barium sulfide, which has the chemical formula BaS. Barium is a group 2 metal with a 2+ charge, and sulfur is a group 16 nonmetal with a 2- charge. Therefore, to balance the charges, one barium ion (Ba2+) combines with one sulfide ion (S2-) to form BaS.
The chemical formula for fluorine is F2, indicating it exists as a diatomic molecule. The chemical formula for barium is Ba.
BaF2, which is called barium fluoride.
i think it is BaF2
Fluorine is an element and barium is also an element. There is no fluorine in barium and not barium in fluorine.
BaF2
This formula tells you that the compound has one atom of the element Barium and two atoms of the element Fluorine. It is called Barium Fluoride.
The formula mass of barium fluoride (BaF2) is calculated by adding the atomic masses of each element in the compound. Barium has an atomic mass of 137.33 g/mol, and fluorine has an atomic mass of 18.998 g/mol. Multiplying the atomic mass of barium by 1 and the atomic mass of fluorine by 2 (because there are two fluorine atoms in the compound) and adding them together gives a formula mass of 175.33 g/mol.
The formula for the compound formed between barium and nitrogen is Ba3N2, which is called barium nitride. Barium has a 2+ charge and nitrogen has a 3- charge, so the formula is derived from their charges balancing out to form a neutral compound.
The compound formed between nitrogen and barium is barium nitride (Ba3N2). The formula indicates that three barium atoms combine with two nitrogen atoms to form the compound.
Some basic information that I'm able to get from the formula BaF2 are: 1) The compound is composed of two different elements, Barium and Fluorine in the ratio of 1:2 2) Barium is a metal and Fluorine is a non-metal therefore BaF2 is formed by ionic bondings and it's an ionic compound 3) Barium donates one electron EACH to two Fluorine and the ions are Ba2+ and 2F- 4) BaF2 is a salt (metal + non-metal) 5) BaF2 has a giant lattice structure
Strontium is a very active alkaline earth metal that is solid at standard temperature and pressure and readily forms divalent cations. Fluorine is a very active nonmetal that readily accepts one additional per atoms, and fluorine at standard temperature and pressure is a diatomic molecular gas. Therefore, these two elements normally react according to the equation: Sr (s) + F2 -> SrF2 (s). The product, a salt named strontium fluoride is a solid at standard temperature and pressure.
The chemical formula for the compound formed between barium and bromine is BaBr2. In this compound, barium forms a +2 cation (Ba^2+) and bromine forms a -1 anion (Br^-), resulting in the formula BaBr2.