The ionic equation for the reaction between copper oxide (CuO) and sulfuric acid (H2SO4) can be written as:
CuO(s) + H2SO4(aq) → Cu2+(aq) + SO42-(aq) + H2O(l)
This equation shows the dissociation of the reactants into their respective ions in solution.
This will depend upon which version of copper oxide you have - copper I oxide or copper II oxide. For copper I oxide: H2SO4 + Cu2O --> Cu2SO4 + H2O For copper II oxide: H2SO4 + CuO --> CuSO4 + H2O
The ionic equation for the reduction of copper sulfate (CuSO4) to copper oxide is: Cu^2+ + 2e^- → Cu This equation represents the reduction half-reaction where copper ions (Cu^2+) gain two electrons to form solid copper (Cu). The formation of copper oxide involves further reactions and would require a more comprehensive equation.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
Copper oxide+ Sulphuric acid ----> copper sulphate +water
When dilute sulphuric acid is added to copper oxide, a chemical reaction occurs, resulting in the formation of copper sulfate and water. The reaction can be represented by the equation: CuO + H2SO4 → CuSO4 + H2O.
This will depend upon which version of copper oxide you have - copper I oxide or copper II oxide. For copper I oxide: H2SO4 + Cu2O --> Cu2SO4 + H2O For copper II oxide: H2SO4 + CuO --> CuSO4 + H2O
The ionic equation for the reduction of copper sulfate (CuSO4) to copper oxide is: Cu^2+ + 2e^- → Cu This equation represents the reduction half-reaction where copper ions (Cu^2+) gain two electrons to form solid copper (Cu). The formation of copper oxide involves further reactions and would require a more comprehensive equation.
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
Copper Oxide reacts with Sulphuric acid to form Copper Sulphate and Water.
Copper oxide+ Sulphuric acid ----> copper sulphate +water
Sulphuric acid is mixed with copper oxide to make copper sulphate through a chemical reaction.
The chemical reaction is:CuO + H2SO4 = CuSO4 + H2O
When dilute sulphuric acid is added to copper oxide, a chemical reaction occurs, resulting in the formation of copper sulfate and water. The reaction can be represented by the equation: CuO + H2SO4 → CuSO4 + H2O.
Yes, copper oxide has ionic bonds. Copper oxide is formed between a metal (copper) and a non-metal (oxygen), resulting in the transfer of electrons from copper to oxygen to form ionic bonds.
Copper(I) oxide has an ionic bond.
CuO is copper (II) oxide, also known as cupric oxide.
Yes, Copper oxide does fizz when it reacts with Sulphuric Acid