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Potassium plus bromine will react to form potassium bromide, which is a white crystalline compound commonly used in various applications such as in photography, pharmaceuticals, and as a flame retardant.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
The formula for the compound of potassium (K) and bromine (Br) is KBr.
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
Potassium plus bromine will react to form potassium bromide, which is a white crystalline compound commonly used in various applications such as in photography, pharmaceuticals, and as a flame retardant.
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
2 dots
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
The formula for the compound of potassium (K) and bromine (Br) is KBr.
Mg2+
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
Because of the number of electrons in the outermost shell of the atom.
It looks like thisK–Br:except that there are also two dots both above and below the "Br" in the diagram (there are three lone pairs on Br, and none on K)See the Related Questions link about Lewis Dot Structures to the left of this answer for more help with electron dot diagrams!
When potassium bromide (KBr) reacts with chlorine gas (Cl2), it forms potassium chloride (KCl) and bromine (Br2). This reaction is a redox reaction, with bromide ions being oxidized to bromine gas and chlorine being reduced to chloride ions.
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.