% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67%
% by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so
39/154 =25%
5
according to the amount we put the change from dark purple to pink color
Not specifically the progress of the purple is caused by flow that was already happening in the water when the crystals were added. Adding the crystal itself only causes a small amount of local disturbance.
yes
Not usually. Potassium iodide is usually present in a large excess. It is usually the potassium iodate that is the limiting ingredient.
its depends in the amount of potassium chloride.
Dissolve a known amount of potassium permanganate in a known volume of demineralized water; calculate the concentration of manganese in the solution.
Potassium permanganate and water form a solution, unless here is so much potassium permanganate present compared to the amount of water that the solubility limit is exceeded. In the latter instance, there might be both solution and suspension.
If the potassium permanganate solution is prepared from stock solid potassium permanganate, it is important to remove manganese dioxide from the system. MnO2 catalytically decomposes permanganate into oxygen and lower ox. states manganese. Manganese dioxide is insoluble, whereas permanganate is very soluble. Boiling the solution would ensure that all solid permanganate had dissolved, and so little would be lost upon filtering out MnO2 (which remains insoluble at higher temperatures) The remaining solution will have a longer shelf-life due to the absence of the aforementioned decomposition catalyst. If the permanganate solution is required acidic, the use of a small amount of phosphoric acid can be effective. Typically, sulfuric acid is used in combination with permanganate as an acid oxidant. The problem being that sulfuric acid dissolves manganese and thus the catalyst becomes soluble, and difficult to remove. Stock acid solutions of permanganate have far reduced shelf-life. The addition of a small amount of phosphoric acid helps alleviate this. Manganese(ii) oxide reacts with acidified permanganate to form Manganese(iii) cations - these in turn precipitate from solution as manganese(iii)phosphate. Complex ions of manganese(iii) can also form with phosphate, and these partake roles in equilibrium resulting in their further deposition from solution. Once the phosphate complexes are removed by filtration of the hot acidified permanganate solution, the solution has a longer shelf-life.
You can decolorize potassium permanganate with something that a considerable amount of Vitamin C. Like orange juice or Lime juice or any citrus fruit for that matter.
according to the amount we put the change from dark purple to pink color
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
Not specifically the progress of the purple is caused by flow that was already happening in the water when the crystals were added. Adding the crystal itself only causes a small amount of local disturbance.
This is more of a math question that requires a bit of knowledge of chemistry. So it helps to know the steps of this answer mathematically. Additionally it's worth noting that there are a number of ways to answer this question. The method I provide may take an extra step, but it allows for a better understanding of the process.First we need to know some basic information about potassium permanganate, KMnO4. This basic information can be found on a periodic table, like the one in the link below. The first step is finding the weight of oxygen in one mole of potassium permanganate as a percent. For this you need to know the atomic weights of the elements involved.K: 39.1 gramsMn: 54.9 gramsO: 16.0 grams × 4 atoms = 64.0 gramsKMnO4: 39.1 + 54.9 + 64.0 = 158.0 grams/molSo now we know the weight of one mole of potassium permanganate (158.0 grams). Because we also know the weight of oxygen, we can find the percent of oxygen in the compound by mass.64.0 grams O ÷ 158.0 grams KMnO4 = 0.405 = 40.5%In one mole of potassium permanganate, 64.0 grams of it is oxygen, meaning 40.5% of it is oxygen. Because of the Law of Definite Proportions, we know that in any amount of potassium permanganate, 40.5% of it is oxygen.Then you can set up an equation.40.5% of (some amount of KMnO4) = 27.5 grams oxygenLet's set the amount of KMnO4 as the variable "x".0.405x = 27.5x = 67.9 grams KMnO4
Potato Calcium Copper Iron Magnesium Manganese Phosphorus Potassium Selenium Sodium Zinc 6 trace amount 0,5 22 trace amount 78 450 0,5 2 0,5
yes
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
No, they have the same amount of potassium either way.