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% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67%

% by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so

39/154 =25%

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Q: What is the amount percentage of manganese in potassium permanganate KMnO4?
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How do you make standard Mn solution?

Dissolve a known amount of potassium permanganate in a known volume of demineralized water; calculate the concentration of manganese in the solution.


Is potassium permanganate and water solution or suspensions?

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What is the importance of boiling KMnO4 solution if it is for future use?

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What happens to the colour of water when potassium permanganate is added?

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How many grams of potassium permanganate KMnO4 are in 2.55 moles?

The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g


Does the colour of potassium permanganate persist when it is added initially?

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How many grams of potassium permanganate contains 27.5 grams of oxygen?

This is more of a math question that requires a bit of knowledge of chemistry. So it helps to know the steps of this answer mathematically. Additionally it's worth noting that there are a number of ways to answer this question. The method I provide may take an extra step, but it allows for a better understanding of the process.First we need to know some basic information about potassium permanganate, KMnO4. This basic information can be found on a periodic table, like the one in the link below. The first step is finding the weight of oxygen in one mole of potassium permanganate as a percent. For this you need to know the atomic weights of the elements involved.K: 39.1 gramsMn: 54.9 gramsO: 16.0 grams × 4 atoms = 64.0 gramsKMnO4: 39.1 + 54.9 + 64.0 = 158.0 grams/molSo now we know the weight of one mole of potassium permanganate (158.0 grams). Because we also know the weight of oxygen, we can find the percent of oxygen in the compound by mass.64.0 grams O ÷ 158.0 grams KMnO4 = 0.405 = 40.5%In one mole of potassium permanganate, 64.0 grams of it is oxygen, meaning 40.5% of it is oxygen. Because of the Law of Definite Proportions, we know that in any amount of potassium permanganate, 40.5% of it is oxygen.Then you can set up an equation.40.5% of (some amount of KMnO4) = 27.5 grams oxygenLet's set the amount of KMnO4 as the variable "x".0.405x = 27.5x = 67.9 grams KMnO4


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Does the amount of potassium iodide added in potassium (V) iodate solution affects the amount of iodine liberated?

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