MgO2
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
It should be 2Mg+O2 = 2MgO, that is an equation (both sides equal).
The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.
The balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) is: 2Mg + O2 -> 2MgO From the balanced equation, it is clear that 1 mole of Mg reacts with 1/2 mole of O2. Therefore, if 4.0 moles of Mg reacts, you would need 2.0 moles of O2.
MgO2
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
The chemical equation representing the reaction of magnesium (Mg) with oxygen (O2) to form magnesium oxide is: 2Mg + O2 → 2MgO The "c" in your equation does not have a clear designation in this context.
2,1,2
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
The symbol equation for the reaction of magnesium with oxygen to form magnesium oxide is: 2Mg + O2 -> 2MgO
It should be 2Mg+O2 = 2MgO, that is an equation (both sides equal).
The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.
This simple equation is: 2H2 + O2 = 2H2O
There are two atoms of oxygen on each side.
The balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) is: 2Mg + O2 -> 2MgO From the balanced equation, it is clear that 1 mole of Mg reacts with 1/2 mole of O2. Therefore, if 4.0 moles of Mg reacts, you would need 2.0 moles of O2.
2Mg + O2 --------> 2MgO