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NaBH4 + 2H2O -> NaBO2 + 4H2 [1]

DeltaG(298K)= -299 kJ/mol BH4

DeltaH(298K)= -231 kJ/mol BH4

(10.8 mass% H)

NaBH4 + 4H2O -> NaB(OH)4 + 4H2 [2]

DeltaG (298K)= -315 kJ/mol BH4

DeltaH = -247 kJ/mol BH4

(7.28 mass% H)

NaBH4 + 6H2O -> NaB(OH)4.2H2O [3]

DeltaG = -319kJ/mol BH4

DeltaH = -213 kJ/mol BH4

(5.48 mass% H)

*Hydrolysis in Eq.[1] is not the most favorable reaction!

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