The balanced equation between potassium dichromate (K2Cr2O7) and oxalic acid (H2C2O4) is:
K2Cr2O7 + 3H2C2O4 -> Cr2(C2O4)3 + 2K2C2O4 + 4H2O
The balanced symbol equation for the reaction between potassium and chlorine is: 2K + Cl2 → 2KCl.
The reaction between glucose and acidified potassium dichromate is the oxidation of glucose to form gluconic acid. The chemical equation for this reaction is: C6H12O6 + H2Cr2O7 + H+ -> C6H11O7COOH + Cr2(SO4)3 + H2O
I think the reaction equation can be written as follows: K2Cr2O7 (aq) + BaCl2(aq) ------ BaCr2O7(s) + 2KCl(aq).
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
The balanced equation for the reaction between potassium dichromate (K₂Cr₂O₇) and ethanol (C₂H₅OH) in an acidic medium is: [ K_2Cr_2O_7 + 3 C_2H_5OH + 8 H^+ \rightarrow 2 Cr^{3+} + 3 CH₃COOH + 2 K^+ + 7 H₂O ] This reaction involves the reduction of potassium dichromate and the oxidation of ethanol to acetic acid.
The reaction between sodium ethanedioate (sodium oxalate) and potassium dichromate can be represented by the following balanced chemical equation: 3 Na2C2O4 + K2Cr2O7 + 4 H2SO4 → 3 Na2SO4 + K2SO4 + Cr2(SO4)3 + 8 CO2 + 7 H2O In this reaction, sodium ethanedioate reacts with potassium dichromate in the presence of sulfuric acid to form sodium sulfate, potassium sulfate, chromium(III) sulfate, carbon dioxide, and water.
The balanced symbol equation for the reaction between potassium and chlorine is: 2K + Cl2 → 2KCl.
The reaction between glucose and acidified potassium dichromate is the oxidation of glucose to form gluconic acid. The chemical equation for this reaction is: C6H12O6 + H2Cr2O7 + H+ -> C6H11O7COOH + Cr2(SO4)3 + H2O
I think the reaction equation can be written as follows: K2Cr2O7 (aq) + BaCl2(aq) ------ BaCr2O7(s) + 2KCl(aq).
The balanced symbol equation between fluorine and potassium chloride is: 2KF + Cl2 -> 2KCl + F2
The reaction between potassium dichromate (K2Cr2O7) and iron(II) sulfate (FeSO4) results in a double displacement reaction producing iron(III) chromate (Fe2(CrO4)3) and potassium sulfate (K2SO4). The balanced equation is: 3FeSO4 + K2Cr2O7 → Fe2(CrO4)3 + K2SO4.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
When iron reacts with potassium dichromate, iron(II) ion is oxidized to iron(III) ion by dichromate, which gets reduced to chromium(III) ion. The balanced chemical equation for this reaction is: 6 Fe^2+ + 14 H^+ + Cr2O7^2- --> 6 Fe^3+ + 2 Cr^3+ + 7 H2O
potassium