Mg (s) + CuSO4 (aq) => Cu (s) + MgSO4 (aq).
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The balanced chemical equation for the reaction between an iron nail (Fe) and copper sulfate (CuSO4) is: Fe + CuSO4 -> FeSO4 + Cu This reaction involves a single displacement reaction where iron displaces copper from copper sulfate to form iron(II) sulfate and copper metal.
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
This equation is CuSO4.5 H2O -> CuSO4 + 5 H2O.
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
The chemical formula (not equation) of copper(II) sulfate is CuSO4.
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The balanced chemical equation for the reaction between an iron nail (Fe) and copper sulfate (CuSO4) is: Fe + CuSO4 -> FeSO4 + Cu This reaction involves a single displacement reaction where iron displaces copper from copper sulfate to form iron(II) sulfate and copper metal.
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
Magnesium + Copper(II) sulfate -> Magnesium sulfate + Copper This balanced equation represents the displacement reaction between magnesium and copper sulfate, where magnesium replaces copper in the compound to form magnesium sulfate while copper is displaced.
The balanced equation for the reaction between aluminum and copper (II) sulfate is: 2Al(s) + 3CuSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Cu(s).
This is a single replacement reaction. Zinc is more reactive than copper, so it replaces it and bonds with sulfate. The balanced equation is Zn + CuSO4 => Cu + ZnSO4 (zinc always has a charge of +2)
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The chemical equation is:CuSO4 + Pb(CH3COO0)2 = Cu(CH3COO)2 + PbSO4(s)