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When silver nitrate solution is reacted with iron metal, a displacement reaction occurs. The iron displaces the silver from the silver nitrate solution, forming iron(II) nitrate and solid silver. The balanced chemical equation for this reaction is: 2AgNO3 + Fe -> 2Ag + Fe(NO3)2.
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
Zn2 + Fe3NO3 -> Zn3NO2 + Fe3
Fe3(PO4)2(aq) + 3AgNO3(aq) --> Fe(NO3)2(aq) + Ag3PO4(s)
2Na + 2Fe(NO3)3 -> 6NaNO3 + 2Fe
When silver nitrate solution is reacted with iron metal, a displacement reaction occurs. The iron displaces the silver from the silver nitrate solution, forming iron(II) nitrate and solid silver. The balanced chemical equation for this reaction is: 2AgNO3 + Fe -> 2Ag + Fe(NO3)2.
The chemical equation is:Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
Zn2 + Fe3NO3 -> Zn3NO2 + Fe3
In fact, there is no chemical reaction between iron (III) nitrate (Fe (NO3)) and sodium chloride (NaCl), so there is no equilibrium chemical equation. Root cause analysis: This is a typical scenario for investigating a double substitution reaction in a complex decomposition reaction. The conditions for the occurrence of the double decomposition reaction are: there must be precipitation, gas, or water (weak electrolyte) in the product. Let's analyze possible products: If a reaction occurs: Fe(NO₃)₃(aq) + 3 NaCl(aq) → FeCl₃(aq) + 3 NaNO₃(aq) Check the product: FeCl ∝ (ferric chloride): soluble in water NaNO ∝ (sodium nitrate): soluble in water All products are soluble strong electrolytes, completely ionized in water, without precipitation, gas or weak electrolyte formation. The ion equation provides a clearer explanation: Reactant ions: Fe³⁺(aq), 3NO₃⁻(aq), 3Na⁺(aq), 3Cl⁻(aq) Product ion: Fe³⁺(aq), 3Cl⁻(aq), 3Na⁺(aq), 3NO₃⁻(aq) All ions are completely identical before and after the reaction, without any chemical changes. Therefore, the net ion equation is: no reaction (or written as "all ions are bystander ions").
The balanced equation for the reaction is: Mg + 2Fe(NO₃)₃ -> Mg(NO₃)₂ + 2Fe
Fe3(PO4)2(aq) + 3AgNO3(aq) --> Fe(NO3)2(aq) + Ag3PO4(s)
2Na + 2Fe(NO3)3 -> 6NaNO3 + 2Fe
The balanced equation for the reaction between iron(III) nitrate and potassium thiocyanate solution is: Fe(NO₃)₃ + 3KSCN → Fe(SCN)₃ + 3KNO₃ Iron(III) nitrate reacts with potassium thiocyanate to form iron(III) thiocyanate and potassium nitrate.
This is a double displacement reaction where iron(II) chloride reacts with silver nitrate to form iron(II) nitrate and silver chloride. The silver chloride precipitates out of the solution as a solid. The balanced chemical equation for the reaction is: 2FeCl2(aq) + 2AgNO3(aq) → 2Fe(NO3)2(aq) + 2AgCl(s)
The chemical equation for iron(III) chloride reacting with silver nitrate is: FeCl3 + 3AgNO3 -> Fe(NO3)3 + 3AgCl
The balanced chemical equation for the reaction between aluminum sulfide and iron II nitrate is: 2 Al2S3 + 3 Fe(NO3)2 -> 2 Al(NO3)3 + 3 FeS