2K(s) + 2H20(l) = 2KOH(aq) + H2(g)
The balanced equation for the decomposition of ammonium hydroxide (NH4OH) into water (H2O) and ammonia (NH3) is: NH4OH -> H2O + NH3
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
The balanced equation for ferric chloride (FeCl3) reacting with sodium hydroxide (NaOH) is: FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
The balanced equation for the reaction between a fatty acid (such as oleic acid) and sodium hydroxide is: Fatty acid + Sodium hydroxide -> Soap (sodium salt of the fatty acid) + Water
the balanced equation for ammonium hydroxide and perchloric acid is given below.NH4OH (aq) + HCl (aq) ---> NH4Cl (aq)+ H2O (l) .Above is the balanced molecular Equation.
The equation is NH4OH + HBr -> NH4Br + H2O.
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
The balanced equation for the decomposition of ammonium hydroxide (NH4OH) into water (H2O) and ammonia (NH3) is: NH4OH -> H2O + NH3
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
2Zn3O2
Any reaction occur.
The balanced equation for ferric chloride (FeCl3) reacting with sodium hydroxide (NaOH) is: FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
The balanced equation for the reaction between a fatty acid (such as oleic acid) and sodium hydroxide is: Fatty acid + Sodium hydroxide -> Soap (sodium salt of the fatty acid) + Water
The balanced equation for hydrochloric acid (HCl) with ammonium hydroxide (NH4OH) is: HCl + NH4OH → NH4Cl + H2O.
The balanced chemical equation for the formation of rubidium hydroxide from rubidium oxide is: 2 Rb2O + 2 H2O → 4 RbOH
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF → KF + H2O.