In hot concentrated acid, nitric is an oxidizing acid:
3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O
But in cold, dilute solutions:
Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
The balanced equation for the reaction between silver metal and nitric acid is: 3Ag(s) + 4HNO3(aq) → 3AgNO3(aq) + 2H2O(l) + NO(g)
2Na(s) +2HNO3(aq) --> 2NaNO3 (aq) + H2 (aq)
what is the balanced equation for Rubidium metal reacting with halogen iodine
Mg (s) + 2 HNO3 (aq) --> H2 (g) + Mg(NO3)2 (aq)
In a chemical equation ,we must finish our chemical reaction with as many atoms of each element as when we started.the balanced chemical equation for the reaction of solid magnesium metal and barium chloride is given as .Mg + Bacl 2 -> Mgcl2 + Ba.
The balanced equation for the reaction between silver metal and nitric acid is: 3Ag(s) + 4HNO3(aq) → 3AgNO3(aq) + 2H2O(l) + NO(g)
if you mean lead the metal: Pb + 2H+ --> Pb+2 + H2
When nitric acid reacts with barium metal, it produces barium nitrate, hydrogen gas, and some water. The balanced chemical equation for this reaction is: 2 Ba + 4 HNO3 → 2 Ba(NO3)2 + 2 H2 + O2.
2Na(s) +2HNO3(aq) --> 2NaNO3 (aq) + H2 (aq)
what is the balanced equation for Rubidium metal reacting with halogen iodine
Mg (s) + 2 HNO3 (aq) --> H2 (g) + Mg(NO3)2 (aq)
In a chemical equation ,we must finish our chemical reaction with as many atoms of each element as when we started.the balanced chemical equation for the reaction of solid magnesium metal and barium chloride is given as .Mg + Bacl 2 -> Mgcl2 + Ba.
The balanced equation for the reaction between calcium metal and aluminum chloride is: 3Ca + 2AlCl3 → 3CaCl2 + 2Al
To write the reaction between magnesium metal and a solution of nitric acid, you would form magnesium nitrate and hydrogen gas. The balanced chemical equation for this reaction is: Mg(s) + 2HNO3(aq) → Mg(NO3)2(aq) + H2(g)
There is NO reaction between Cu and Ag.
The balanced equation for the reaction of magnesium metal with aluminum ions is: 2Al^3+ + 3Mg -> 2Al + 3Mg^2+. In this reaction, magnesium metal displaces aluminum ions to form aluminum metal and magnesium ions.
Pieces of copper are added to hot concentrated solutions of hydrochloric, phosphoric, sulfuric and nitric acids. A reaction clearly takes place between copper and nitric acid. The presence of copper ions can be observed by adding each solution to a dilute solution of ammonia. If copper ions were present, we would see the blue color of the copper-ammonia complex. Sulfuric acid has oxidized the copper metal, as indicated by the blue color. Nitric acid is a stronger oxidizing agent (and produces a higher concentration of copper(II) ions), as indicated by the darker blue color.