The reaction is:
3 CuSO4 + 2 K3PO4 = Cu3(PO4)2 + 3 K2SO4
The balanced molecular equation for copper(II) sulfate and potassium phosphate is:
3CuSO4(aq) + 2K3PO4(aq) --> Cu3(PO4)2(s) + 3K2SO4(aq)
This is a double replacement reaction, also called a double displacement reaction or a metathesis reaction. In this type of reaction, the positive and negative ions in the reactants switch places to form the products. The products must include a solid (precipitate), an insoluble gas that bubbles out of solution, or water. If none of those are present in the products, then their was no reaction. The general equation for a double replacement reaction is AB + CD --> AD + CB, in which A and C are the positive ions, and the B and D are the negative ions.
The balanced molecular equation for copper(II) sulfate and potassium phosphate is:
3CuSO4(aq) + 2K3PO4(aq) --> Cu3(PO4)2(s) + 3K2SO4(aq)
This is a double replacement reaction, also called a double displacement reaction or a metathesis reaction. In this type of reaction, the positive and negative ions in the reactants switch places to form the products. The products must include a solid (precipitate), an insoluble gas that bubbles out of solution, or water. If none of those are present in the products, then their was no reaction. The general equation for a double replacement reaction is AB + CD --> AD + CB, in which A and C are the positive ions, and the B and D are the negative ions.
The reaction is:
3 CuSO4 + 2 K3PO4 = Cu3(PO4)2 + 3 K2SO4
3Ba(BrO3)2 + 2Na3PO4 -> Ba3(PO4)2 + 6NaBrO3
CH3COOH + KOH = CH3COOK + H2O
3 K2Cr2O7 + 2 (NH4)3PO4 ------------3 (NH4)2Cr2O7 + 2 K3PO4
give me balanced equation for potassium gold cyanide? give me balanced equation for potassium gold cyanide?
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
Nothing happens, all possible salts are very soluble: Potassium and sodium salts are always soluble!
3Ba(BrO3)2 + 2Na3PO4 -> Ba3(PO4)2 + 6NaBrO3
CH3COOH + KOH = CH3COOK + H2O
Zn(NO3)2 + Na3PO4 yields Zn3(PO4)2 + NaNO3 with zinc phosphate being the precipitate.
3 K2Cr2O7 + 2 (NH4)3PO4 ------------3 (NH4)2Cr2O7 + 2 K3PO4
Do you want that for Monopotassium phosphate, dipotassium phosphate, or tripotassium phosphate? --------------------------------- To clarify for the previous answerer, ionic compounds inherently don't use the mono-, di-, or tri- system used for molecular compounds. Instead, when a cation and an anion is supplied, the ionic compound assumes the number of cations and anions that will generate a neutral ionic compound. In this case, since K is 1+ and PO4 is 3-, the compound potassium phosphate always refers to K3PO4. Therefore: 3AgNO3 + K3PO4 -> 3KNO3 + Ag3PO4
It would be2 K3PO4 + 3 Co(NO3)2 = Co3(PO4)2 + 6 KNO3
give me balanced equation for potassium gold cyanide? give me balanced equation for potassium gold cyanide?
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
The chemical formula (not equation) is KClO3
3CuCl2(aq)+2(NH4)3PO4(aq) Cu3(PO4)2(s)+6NH4Cl(aq)
If you mean the chemical formula, it is Ag3PO4