Your balanced chemical equation for this double replacement reaction would be:
Cu(NO3)2 + 2KOH ----> Cu(OH)2 + 2KNO3
Therefore, you would end up with copper II hydroxide and potassium nitrate.
copper nitrate + Potassium carbonate = Copper carbonate + potassium nitrate....i believe.
The chemical equation is:
Cu(NO3)2 + 2 KOH = 2 KNO3 + Cu(OH)2(s)
Cu(NO3)2 + NaCO3
react to give potassium nitrate plus water.
The chemical reaction is: NH4NO3 + NaOH ---------→ NH3 + H2O + NaNO3
Potassium Nitrate+Water HNO3 (aq)+KOH (aq)-->KNO3 (aq)+H2O (l)
The stated reaction is an example of a neutralization reaction between an acid and a base forming a product salt and water. The equation of the reaction is HNO3 + KOH -> KNO3 + H2O.
Potassium nitrate
You would add either ammonium nitrate or nitric acid.
Products are potassium nitrate and water. Here is the Word Equation Potassium hydrtoxide + nitric Acid = potassium nitrate and water. Here is the BALANCED reaction eq'n KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l) NB THere will be no precipitate. To isolate the product you need to evaporate the solution. NNB All Group (1) metal cations (K^+) and nitrate anions(NO3^-) are soluble.
Kn2 heat equal kn2+o2
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
react to give potassium nitrate plus water.
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Potassium form in water potassium hydroxide; so the reaction will be:2 KOH + Zn(NO3)2 = 2 KNO3 + Zn(OH)2(s)
The chemical reaction is: NH4NO3 + NaOH -----→ NH3 + H2O + NaNO3
The chemical reaction is: NH4NO3 + NaOH ---------→ NH3 + H2O + NaNO3
Potassium Nitrate+Water HNO3 (aq)+KOH (aq)-->KNO3 (aq)+H2O (l)
Potassium nitrate
The stated reaction is an example of a neutralization reaction between an acid and a base forming a product salt and water. The equation of the reaction is HNO3 + KOH -> KNO3 + H2O.