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This is a double-replacement reaction. The charges of each cation and anion are:

Copper (II): 2+

Nitrate: 1-

Sodium: 1+

Hydroxide: 1-

This means that the equation without coefficients would be

Cu(NO3)2 + NaOH --> NaNO3 + Cu(OH)2.

Since there is an uneven number of nitrates and hydroxides, coefficients must be added before NaOH and NaNO3 to make the equation balanced.

Cu(NO3)2 + 2NaOH --> 2NaNO3 + Cu(OH)2
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