The balanced equation for the reaction between Ag₂S and O₂ to produce Ag and S₈ is:
2Ag₂S + 11O₂ → 2Ag + 4SO₂
The above reaction is a combination type reaction between silver (Ag) and sulfur (S)
The chemical equation for the formation of silver sulfide when silver and sulfur react is: 8 Ag + S8 -> 8 Ag2S
In silver sulfide (Ag2S), each silver (Ag) atom has an oxidation state of +1, and each sulfur (S) atom has an oxidation state of -2. This arrangement balances out the charges to form a neutral compound.
The tarnish of silver is mainly caused by the formation of silver sulfide (Ag2S) when silver reacts with sulfur compounds in the air. The chemical equation for this reaction is: 2Ag + H2S + O2 → Ag2S + H2O
Ag2S is Ionic. If it has a Non-Metal and a Metal it is Ionic. If it only contains non-metals it is noniconic. Well that simple rule is OK- however a better guess is made if you conside the electronegativities of Ag and S - they are quite close (they need to be well apart for ionic bonding) so Ag2S has considerable covalent character.
The balanced chemical equation for the reaction between silver and sulfur (S8) to form silver sulfide (Ag2S) is 8Ag + S8 -> 8Ag2S.
The above reaction is a combination type reaction between silver (Ag) and sulfur (S)
The chemical equation for the formation of silver sulfide when silver and sulfur react is: 8 Ag + S8 -> 8 Ag2S
The way to solve these problems is to determine which reactant will produce the fewest moles of product. In order to do this, we first need to convert the mass of each reactant into moles of reactant using the molecular mass of silver, Ag (107.9 g/mol), and molecular sulfur, S8 (256.5) g/mol:2.0 g Ag * 1mol/107.9 g/mol = 0.0185 mol Ag2.0 g S8 * 1mol/256.5 g/mol = 0.00779 mol S8Now using the balanced chemical equation (our recipe) from above:16 Ag + S8 -->8 Ag2SWe can see:16 moles of Ag turns into 8 moles of Ag2S1 mole of S8 turns into 8 moles of Ag2SWhat we need to do know, is use these two statements above to see how many moles of product each reactant turns into:0.0185 mol Ag * 8 mol Ag2S/16 mol Ag = 0.00925 mol Ag2S0.00779 mol S8 * 8mol Ag2S/1 mol S8 = 0.0623 mol Ag2SSince 0.0185 mole of Ag produce less Ag2S (the product), silver (Ag) is the limiting reactant. Now you could convert this to grams of product by multiplying the lesser amount produced, 0.00925 moles of Ag2S, by the molecular mass of Ag2S.To determine the mass of reactant left unreacted, we need to convert moles of the limiting reactant into moles of the other reactant to find out how much of the other reactant is lost--Then subtract from the original amount and convert to grams with the molecular mass.0.0185 mol Ag * 1 mol S8/16 mol Ag = 0.00116 mol S8Originally we had 0.00779 mol of S8, from above, so:0.00779 mol S8 - 0.00116 mol S8 = 0.00663 mol S8Now convert to grams left:0.00663 mol S8 * 256.5 g/mol = 1.70 g S8 left unreacted!
1 mol Ag/ 107.87g Ag ---/---------------------------------------- x2=215.74g Ag / 1mol Ag 1 mol S/32.07g S --------/------------------------------------32.07g S /1 mol S total=247.81g Ag2S 215.47g Ag/247.81=.8706 87.06% Ag .8706 or 87.06% Ag x 125g Ag2S = 108.83g Ag can be produced from Ag2S
To find out how much silver can be produced from 125g of Ag2S, you need to consider the molar mass of Ag2S, which is 247.8 g/mol. This means that 1 mole of Ag2S produces 2 moles of silver (Ag). Therefore, you can calculate the amount of silver produced from 125g of Ag2S using stoichiometry.
To balance the equation Ag + H2S → Ag2S + H2, you need to make sure that the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 2 in front of Ag and Ag2S to balance the silver atoms. Then, balance the hydrogen atoms by adding a coefficient of 2 in front of H2. Finally, balance the sulfur atoms by adding a coefficient of 2 in front of H2S. The balanced equation is 2Ag + 2H2S → Ag2S + H2.
The mole ratio of H2S to Ag2S can be derived from the balanced chemical equation for the reaction between hydrogen sulfide (H2S) and silver sulfide (Ag2S). The balanced equation is typically represented as 2 H2S + Ag2S → 4 Ag + 2 H2O + 2 S. From this equation, the mole ratio of H2S to Ag2S is 2:1.
In silver sulfide (Ag2S), each silver (Ag) atom has an oxidation state of +1, and each sulfur (S) atom has an oxidation state of -2. This arrangement balances out the charges to form a neutral compound.
The tarnish of silver is mainly caused by the formation of silver sulfide (Ag2S) when silver reacts with sulfur compounds in the air. The chemical equation for this reaction is: 2Ag + H2S + O2 → Ag2S + H2O
(2 Na+ + HS- + OH-)(aq) + 2 (Ag+ + [NO3]-)(aq) ---------- Ag2S(S) + 2 (Na+ + [NO3]-)(aq) + H2O
Ag2S is Ionic. If it has a Non-Metal and a Metal it is Ionic. If it only contains non-metals it is noniconic. Well that simple rule is OK- however a better guess is made if you conside the electronegativities of Ag and S - they are quite close (they need to be well apart for ionic bonding) so Ag2S has considerable covalent character.