The conjugate base for the hydronium ion (H3O+) is indeed water
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
The conjugate base of H3O+ is H2O (water). This is because when H3O+ donates a proton (H+ ion), it forms the conjugate base H2O by losing a hydrogen ion.
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
The conjugate base differs ONE proton (less) than the acid.H3O+ --> H2O + H+so H2O is the conjugate base of H3O+
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
H3O is a strong acid.
The conjugate base of H3O+ is H2O (water). This is because when H3O+ donates a proton (H+ ion), it forms the conjugate base H2O by losing a hydrogen ion.
Cu+ H2O [OH + H3O= 2H2O]Copper plus more than one water = [CuOH + H3O]
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
The conjugate base differs ONE proton (less) than the acid.H3O+ --> H2O + H+so H2O is the conjugate base of H3O+
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
In the reaction provided, H2SO4 is acting as an acid because it donates a proton (H+) to water (H2O), forming H3O+ and HSO4-. The water molecule accepts the proton, forming the hydronium ion (H3O+), while the bisulfate ion (HSO4-) is left with the negative charge.
In pure water, the concentration of H3O plus (hydronium ion, H3O+) is 1.0 x 10^-7 mol/L and the concentration of OH- (hydroxide ion) is also 1.0 x 10^-7 mol/L. This represents a balanced state of neutrality.
Hydronium ions have the formula H3O+
A basic solution has more OH- ions A solution with more H3O+ is acidic.
dissociation of acid in water: A + H2O <-> A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O <-> HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O <-> H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].