1/2
The bond order of B2-1 is 1. This is because it has 1 electron more than the neutral boron molecule B2, which increases the number of bonding electrons, resulting in a bond order of 1.
The expected bond order for diatomic B2 is 1, calculated by subtracting the number of antibonding electrons from the number of bonding electrons in the molecular orbital diagram.
Do you meann Br2? there is no B2 diboron species as far as I know. Br2 has a bondl length of 228 pm
The bond order of C2 in this excited state is 1/2 (6-2) = 2. There are six bonding electrons and two antibonding electrons.
The bond order of NO+ is 2.5, which indicates a bond that is between a single and a double bond. This is because there are 11 valence electrons shared between the nitrogen and oxygen atoms, giving rise to a half-filled molecular orbital.
3/2 and paramagnetic
The bond order of B2-1 is 1. This is because it has 1 electron more than the neutral boron molecule B2, which increases the number of bonding electrons, resulting in a bond order of 1.
The expected bond order for diatomic B2 is 1, calculated by subtracting the number of antibonding electrons from the number of bonding electrons in the molecular orbital diagram.
Do you meann Br2? there is no B2 diboron species as far as I know. Br2 has a bondl length of 228 pm
(-8 + b2) - (5 + b2) = -8 + b2 - 5 - b2 = -13
You can decrease the bond order of a molecule like F2 or B2 by adding 1 electron to the neutral molecule.
24a + b2 + 3a + 2b2= 27a + 3b2
a2+2a2b+2ab2+b2
The equation (b2 - 2b) + (3b - 6) = b2 + b - 6
The polynomial IS b2 - 6b + 8.
The bond order of C2 in this excited state is 1/2 (6-2) = 2. There are six bonding electrons and two antibonding electrons.
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.