It depends on the charge of the cation. Examples NaCl, MgCl2, FeCl3
Magnesium is a group II metal and chlorine is a nonmetal halogen. So,Mg 2+ ( as the cation )and2Cl - ( as the anion )would form the ionic bond,MgCl2
MgCl2=95grams per mole so 105g/95g is 1.10 mols of MgCl2
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
It depends on the charge of the cation. Examples NaCl, MgCl2, FeCl3
Magnesium is a group II metal and chlorine is a nonmetal halogen. So,Mg 2+ ( as the cation )and2Cl - ( as the anion )would form the ionic bond,MgCl2
MgCl2 is magnesium chloride.
MgCl2=95grams per mole so 105g/95g is 1.10 mols of MgCl2
positive ion - magnesium(cation) negative ion-chloride (anion)
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
The synthesis equation for MgCl2 is Mg + Cl2 -> MgCl2. The decomposition reaction is MgCl2 - heat-> Mg + Cl2.
MgCl2
yes mgcl2 is aqous solution
No, MgCl2 is not a base. It is a type of salt that is known for its high solubility in water.
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------