Since oxygen atoms can only accept two electrons, the balance of charges for the overall neutral molecule suggests that the two chromium atoms must each have donated half of the electrons to the oxygen atoms. Therefore, the total number of electrons required for all three oxygen atoms to reach a noble gas configuration is
3 atoms*2 electrons/atom=6 electrons
Dividing this up between the two chromium atoms:
6 electrons/2 atoms=3 electrons/atom
Therefore, each chromium atom bears a positive charge (since it donated electrons) of 3+.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.
Chromium (Cr) typically has a charge of +3 or +6 in ionic compounds.
The answer is + 6 The way I figured it out was that O has a -2 charge. -2 times 7 is - 14. to leave -2 you need a +12 charge. So you divide 12 by 2 because you have 2 Cr and you get 6
The charge on chromium in the complex Cr(NH)Br is 3.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.
Chromium (Cr) typically has a charge of +3 or +6 in ionic compounds.
The answer is + 6 The way I figured it out was that O has a -2 charge. -2 times 7 is - 14. to leave -2 you need a +12 charge. So you divide 12 by 2 because you have 2 Cr and you get 6
+2
The charge on chromium in the complex Cr(NH)Br is 3.
A dichromate ion (Cr2O7^2-) contains a total of 9 atoms - 2 chromium (Cr) atoms and 7 oxygen (O) atoms.
3 +
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
Fe2(Cr2O7)3
The oxidation number of Cr in Cr3+ is +3. This is because each Cl ion has a charge of -1, and since the compound is neutral, the total positive charge from Cr must equal the total negative charge from the Cl ions.
+6This compound has dichromate in it (Cr2O7-2). Oxygen almost always has an oxidation state of -2, which means the total charge for the oxygens is -14. The charge on the two chromates combined needs to be two less than the total charge on the oxygens because the ion has an overall charge of -2. Thus, the oxidation state for Cr is +6.