You have to balance the valence between the metal and Cl. Cl wants one electron, so it has a charge of -1. It takes one alkali metal to balance that charge, since alkali metals only give up one electron. This means XCl is made of an alkali metal. Alkaline earth metals give up two electrons, and so it can give one of those two electrons to two Cl. Therefore, XCl2 contains an alkaline earth metal
The charge is 3-.
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A proton has a positive charge of 1.602 x 10-19 coulomb.
yes, a positive charge (p+)
group 2 because Cl is in group 7a with a charge of -1 and multiplied by 2 gives you -2. Balancing this equation out requires X being +2. Hope that helps.
You have to balance the valence between the metal and Cl. Cl wants one electron, so it has a charge of -1. It takes one alkali metal to balance that charge, since alkali metals only give up one electron. This means XCl is made of an alkali metal. Alkaline earth metals give up two electrons, and so it can give one of those two electrons to two Cl. Therefore, XCl2 contains an alkaline earth metal
The charge is 3-.
When "x" valence electrons are lost the charge is +x When "x" valence electrons are gained the charge is -x for example, if chlorine gained one electron, the charge would be Cl 1- or, if magnesium lost two electrons, the charge would be Mg 2+
Letter X could be any element. It has charge depending on name of element.
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x-rays cost alot of money
A proton has a positive charge of 1.602 x 10-19 coulomb.
yes, a positive charge (p+)
An electron has a charge of -1.6 x 10 (to the negative 19th power) C The neutron has no charge at all. Thus the net charge is that of the electron. -1,6 x 10(-19th power).
In order to identify the charge of a body we should use a charged electroscope. Let us say the electroscope is negatively charged. Now bring the unknown charged body 'X' near the cap of the electroscope. If the leaves diverge more the charge in 'X' must be negative. Suppose that the leaves close a little when 'X' is brought near 'C', then 'X' may have a positive charge or it may not have any charge. In order to confirm the positive charge you must bring the rod 'X' near the cap of a positively charged electroscope. If the leaves diverge more, then 'X' has positive charge.
The measurement of charge is not correct as it is not the integral multiple minimum charge(that is 1.6 x 10-19C). However , there is your answer Charge on a body is given by,q = ne Therefore , required no. of electrons,n = q/e = 3.45 x 10-17 /1.6 x 10-19 = 2.15625 x 102