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Au2(SiO3)3 is a good guess for an imagianry compound. Gold silicates are not known. This would require the reaction of gold(III) oxide with silica- as gold(III) oxide decomposes at 160 0C what you get with silca are lovey ruby glasses or cranberry glasses that contain colloidal gold metal. In nature gold is found as small particulates in some silicate rocks.

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11y ago
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Jëffër Hürtädö

Lvl 1
2mo ago
Como se llama esa formula
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10y ago

One way of writing the formula is Au4[Fe(CN)6]3: The formula for a gold (III) cation is Au+3, which has a positive electric charge of 3. The formula for a cyanide ion is CN-1, and the words "ferrate (II)" mean that the formal charge on the iron atom in the complex anion is +2 units. Therefore, the total charge on the complex anion Fe(CN)6 is -4, that is -6 +2. Therefore, 3 complex anions are required to balance the total charge of each four Au+2 cations.

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15y ago

It is Au(IO3)3. I am not sure of the formula for iodate though.

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Wiki User

6y ago

The chemical formula for gold(III) oxide is Au2O3.

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12y ago

Formula: Au(OH)3

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12y ago

Formula: Au2(Cr2O7)3

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12y ago

Formula: Au2(SO4)3

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13y ago

Au(ClO3)3

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Wiki User

15y ago

AuCl3

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Q: What is the chemical formula for Gold(I) oxide?
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