That would be chromium(IV) selenide with the formula CrSe2
The compound formed between chromium(VI) and chlorine is chromium(VI) chloride, with the chemical formula CrCl6.
Sodium selenide is a compound formed between sodium and selenium.
The manganese(IV) selenide has the chemical formula MnSe2.
Chromium(III) borate has the chemical formula CrBO3.
The answer from my chem class states its Cr(NO3)2
The compound formed between chromium(VI) and chlorine is chromium(VI) chloride, with the chemical formula CrCl6.
The compound formed between iron and selenium is iron(II) selenide, with the chemical formula FeSe.
Sodium selenide is a compound formed between sodium and selenium.
The manganese(IV) selenide has the chemical formula MnSe2.
The compound formed between lithium and selenium would have the chemical formula Li2Se. This is because lithium is in Group 1 of the periodic table and has a +1 charge, while selenium is in Group 16 and has a -2 charge.
The chemical formula for the compound formed between sodium and selenium is Na2Se. Sodium has a +1 charge, and selenium has a -2 charge, so two sodium atoms combine with one selenium atom to form a stable compound.
The compound formed between sodium and selenium is sodium selenide (Na2Se). It is an inorganic compound that consists of sodium cations (Na+) and selenide anions (Se2-). Sodium selenide is often used in chemical synthesis and as a precursor for other selenium-containing compounds.
Chromium(III) borate has the chemical formula CrBO3.
The answer from my chem class states its Cr(NO3)2
Carbon dioxide is not part of sulfur, tellurium, selenium, or polonium. Carbon dioxide is a compound composed of carbon and oxygen atoms. Sulfur, tellurium, selenium, and polonium are elements on the periodic table that do not contain carbon or oxygen in their chemical structures.
Ammonium Chromate and Lead(II) Nitrate form Ammonium Nitrate and Lead(II) Chromate through a double-displacement reaction.
The chemical equation for the reaction between barium and selenium is: Ba + Se → BaSe. This reaction forms barium selenide.