The coefficient for oxygen (O2) would differ depending on where it is diffused. Please see Related Links for reliable formulas to figure the coefficients in different situations.
As stated in the question, it is 1.
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
4K + O2 = 2K2O so the "coefficient" is 1
Because there are 2 oxygen atoms on the reactants side and only one on the products side. You can either add a coefficient of 1/2 on the O2 or you can add a coefficient of 2 on H2 and H2O.
The coefficient of O2 is 5.The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
2
5
5
the answers is 6 _apex
The coefficient of Fe2O3 is 1
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
4K + O2 = 2K2O so the "coefficient" is 1
6
Because there are 2 oxygen atoms on the reactants side and only one on the products side. You can either add a coefficient of 1/2 on the O2 or you can add a coefficient of 2 on H2 and H2O.
Coefficient