The complete ionic equation would be2Na^2(aq) + SO4^2-(aq) + Ca^2+(aq) + 2Cl^-(aq) =>2Na^+(aq) + 2Cl^-(aq) + CaSO4(s)
SO4²-(aq)+ CaCl2(aq)----> CaSO4(s)
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
cacl2 plus na2s equals cas plus
total ionic equation (also known as the complete ionic equation) for the reaction of potassium carbonate with hydrochloric acid
ionic
Molecular_equation_of_copper_II_sulfate_plus_sodium_carbonateCuSO4 + NaCO3 -------> Na2SO4 + CuCO3chebs
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
cacl2 plus na2s equals cas plus
the spectator ions are removed
total ionic equation (also known as the complete ionic equation) for the reaction of potassium carbonate with hydrochloric acid
ionic
Ionic
CaCl2 is an ionic compound forming a giant lattice.
Ca (2+) + CO3 (2-) --> CaCO3
You should have written CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s) (The Precipitation reaction) The full ionic equation though is ............................. Ca2+ + 2Cl- + 2Ag+ + 2NO3- → Ca2+ + 2NO3- + 2AgCl(s)
NO!!! It is TWO(2) ionic bonds. CaCl2 = Ca^(2+) + Cl^(-) + Cl^(-)