potassium dichromate
Yes, K2Cr2O7 (potassium dichromate) is an ionic compound. It is composed of potassium ions (K+) and dichromate ions (Cr2O7^2-), which are held together by ionic bonds.
In K2Cr2O7, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in the dichromate ion (Cr2O7)^2-, the total oxidation number contribution from oxygen is -14. To balance this, the oxidation number of Cr is +6. Therefore, the oxidation number of O in this compound is -2.
First, calculate the number of moles for each element: K = 0.89 g / 39.10 g/mol = 0.023 mol, Cr = 1.18 g / 51.99 g/mol = 0.023 mol, and O = 1.27 g / 16.00 g/mol = 0.079 mol. Next, determine the mole ratio of each element by dividing by the smallest number of moles (0.023 mol in this case) to get K: 1, Cr: 1, and O: 3. Thus, the empirical formula of the compound is KCrO3.
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Yes, K2Cr2O7 (potassium dichromate) is an ionic compound. It is composed of potassium ions (K+) and dichromate ions (Cr2O7^2-), which are held together by ionic bonds.
In K2Cr2O7, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in the dichromate ion (Cr2O7)^2-, the total oxidation number contribution from oxygen is -14. To balance this, the oxidation number of Cr is +6. Therefore, the oxidation number of O in this compound is -2.
First, calculate the number of moles for each element: K = 0.89 g / 39.10 g/mol = 0.023 mol, Cr = 1.18 g / 51.99 g/mol = 0.023 mol, and O = 1.27 g / 16.00 g/mol = 0.079 mol. Next, determine the mole ratio of each element by dividing by the smallest number of moles (0.023 mol in this case) to get K: 1, Cr: 1, and O: 3. Thus, the empirical formula of the compound is KCrO3.
It is a compound.
Water is a compound
Compound.
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Peach is a compound
Compound