What is the concentration of a solution prepared by mixing 100g of salt with 500 ml of water?

Answer 1

500 mL water = 500 g water

Plus 100 g of salt

_______________________ +

600 g of salt solution

with concentration (100g / 600g) * 100% = 16.7% (by mass)

Please note that you don't know the total volume of the solution, but it is less than 600 mL. (Its density is more than the 1.00 g/mL for water)

Answer 2

When 50 g of salt (NaCl; sodium chloride) is dissolved in 200 ml of water, there are several ways to express the concentration. It can be expressed as g/ml, in which case the concentration will be 0.005 g/ml. Or, it can be expressed as percent mass/volume, in which case the concentration will be 25g/100ml = 25% m/v. Or, most conventionally, it can be expressed as moles/liter (M), in which case it will be 50 g x 1 mol NaCl/58,44g/0.200 L = 4.28 M.

Answer 3

If by "salt" one is referring to sodium chloride (NaCl), then the following applies:
molar mass NaCl = 58.4 g/mole ... 50 g x 1 mol/58.4 g = 0.856 moles NaCl
0.856 moles/0.2 L = 4.28 M ... this would be the concentration

Answer 4

If by salt, you mean NaCl, then 50 g NaCl x 1 mole NaCl/58.4 g = 0.856 moles
0.856 moles NaCl/0.2 kg= 4.28 molal = 4.28 m = 4.3 m (2 sig figs)
NOTE: You cannot calculate the molarity (M) without knowing the final volume. Adding 50 g salt to 200 ml will NOT end in a final volume of 200 ml. It will be somewhat greater than that.

Answer 5

18 g at 20 0C.

Answer 6

You will get a salt solution.

Answer 7

The concentration is 250 g/L.

Answer 8

.25g/ml

Answer 9

205 g