In this reaction, the total number of atoms of each element remains the same on both sides: 2 H atoms on the left equal 2 H atoms on the right, and 2 Cl atoms on the left equal 2 Cl atoms on the right, showing that mass is conserved in a chemical reaction.
Its 0
Yes, the equation obeys the law of conservation of matter. The number of atoms for each element is the same on both sides of the equation, indicating that no atoms are created or destroyed during the reaction.
The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1. For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.
3H2(g) + N2(g) ---> 2NH3(g)
Based on the ideal gas law at STP (standard temperature and pressure), the volume occupied by 3.00 mmol of H2 gas would be 67.2 mL (Choice B). This calculation is done using the equation V = nRT/P, where R is the gas constant, T is the temperature, P is the pressure, n is the number of moles, and V is the volume.
Keq = [H2O][CO] [H2][CO2]
Its 0
HI will be consumed. The reaction will proceed to the left. More I2 will form.
The correct form for the equilibrium constant expression for this reaction is Kc = [HF]^2 / ([H2] * [F2]), where the square brackets denote molar concentrations of each species at equilibrium.
The equilibrium constant, K_eq, for the reaction 2HCl(g) ⇌ H2(g) + Cl2(g) is equal to the concentration of H2 and Cl2 divided by the concentration of HCl squared, as products are in the numerator and reactants in the denominator.
In:(H2)g oxidation state: 0 In:(O2)g oxidation state: 0 In:(H2O)l oxidation state: H: +1 and O: -2
Yes, the equation obeys the law of conservation of matter. The number of atoms for each element is the same on both sides of the equation, indicating that no atoms are created or destroyed during the reaction.
Please provide more information/context/clarification to help us answer this question. You can post your response in this answer text by clicking "Edit."
Please provide more information/context/clarification to help us answer this question. You can post your response in this answer text by clicking "Edit."
The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1. For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.
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3H2(g) + N2(g) ---> 2NH3(g)