answersLogoWhite

0

I believe that this value is 23,96.

User Avatar

Wiki User

13y ago

What else can I help you with?

Continue Learning about Chemistry

If it requires 40 ml of 3.5 m naoh to neutralize 55 of hcl what is the molarity of the hcl solution?

40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M


What percent of 40 is 12?

12/40 x 100 % = 30 % Checking: 30% of 40 = 30/100 x 40 = 0.3 x 40 = 12


Why hcl is 37 percent pure only?

HCl is usually prepared by dissolving Hydrogen Chloride into water, but as we increase the concentration of HCl its boiling point starts to decrease (10% HCl has boiling point of 103 C and 38% has 48 C), so at concentration over 38 the rate of evaporation becomes so high that extra precautions has to taken for storage and handling (like low temperatures and high pressure), Thats why it is not safe to produce HCl over 40%. And as the rate of evaporation at even 38% is quite high it is called fuming HCl acid.


How much 66 baume sulfuric acid is required to neutralize 350lbs of sodium hydroxide?

66 Baume Sulfuric Acid is contains 93.2% H2SO4 by weight in water. It requires 1 lbmol of H2SO4 to neutralize 2 lbmol of NaOH. Assuming that 350 lbs of NaOH is pure, there are 8.75 lbmol of NaOH. (Divide 350lb by 40 lb/lbmol, the MW of NaOH.) It takes 4.375 lbmol of H2SO4 to neutralize the 350 lb of NaOH because there are 2 lbmol of H per lbmol of H2SO4 and one lbmol of OH per lbmol of NaOH. 4.375 lbmol is equivalent to 428.75 lb of H2SO4. (Multiply by 98 lb/lbmol, the MW of H2SO4.) Then divide by 93.2% or 0.932 to get the quanty of 66 Baume containing 428.75 lb of H2SO4. 460 lb of 66 Baume. The density of 66 Baume is 1.8354 g/cm3 which is equivalent to 15.32 lb/gallon. (Mulitply by 8.345.) Finally, it requires 30 gallons of 66 baume to neutralize 350 lbs of NaOH. (Divide 460 by 15.32.)


How can you make 500ml of 0.8M HCl solution from 10M HCl and water?

Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.